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Analog outputs

Created by: Nigelms at: 8/16/2011 3:58 AM (3 Replies)

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8/16/2011 3:58 AM	Rate (0)
Nigelms Posts: 4 Rating: (0)	Hello I saw a lot of helpful explanations on analog inputs but I would like some help with an analog output.I would like my program to operate like a repeater by sending an analog input 4-20mAin an AI card and outputing the same signal 4-20mA on an output card. Can you give me hints on how to structure this? and also I would like to get a resolution of 0.01mA.Using either LAD or FBD Any help is appreciated...Thanks!
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8/16/2011 6:05 AM	Rate (0)
Amit_86 Posts: 1750 Rating: (272)	Hello, You need to use Scaling block(FC105) & Unscaling blcok(FC106) together to acheive your requirment. & the resolution of the Current Signal depends on module you are using in your application.
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8/16/2011 6:09 AM	Rate (0)
hdhosseini Diamond Expert Joined: 1/28/2009 Last visit: 1/5/2026 Posts: 6892 Rating: (1368)	Nigelms Hello I saw a lot of helpful explanations on analog inputs but I would like some help with an analog output.I would like my program to operate like a repeater by sending an analog input 4-20mAin an AI card and outputing the same signal 4-20mA on an output card. Can you give me hints on how to structure this? Hi What about using MOVE fncion in LAD/FBD? Regards
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8/16/2011 9:04 AM

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Ayman Elotaify

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Nigelms
Hello

I saw a lot of helpful explanations on analog inputs but I would like some help with an analog output.I would like my program to operate like a repeater by sending an analog input 4-20mAin an AI card and outputing the same signal 4-20mA on an output card. Can you give me hints on how to structure this? and also I would like to get a resolution of 0.01mA.Using either LAD or FBD

Any help is appreciated...Thanks!

Hello,

Please descripe in details your application.
Please tell us the MLFB of both AI & AO modules, in order to know the resolution of both of them.
Please have a look on thisthread, you will find there an example on how to calculate the resolution in electrical units

Now let us calculate what is the required resolution for achieving 0.01mA precision.

+27648 = +20 mA
0 = 4mA

Each 1 unit = 1*slope = 1*[(20-4)/(27648-0)] = (16/27648) = 0.00058 mA.

And according to the following table:

Bit No.

Min. Units

Bit Value

Dec

Hex

2^14

2^13

2^12

2^11

2^10

2^9

2^8

2^7

2^6

2^5

2^4

2^3

2^2

2^1

2^0

Resolution in bits + sign

128

For 8 bit resolution module => Min units = 128, res. =0.00058 * 128 = 0.07424 mA

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Analog outputs

Created by: Nigelms at: 8/16/2011 3:58 AM (3 Replies)

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Analog outputs

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