Ella_68

Hello John0169,

Here is a solution:

Every input is assigned a continuous value through a chain of muxers (I1=1 ...I10=10). If an input is occupied, a counter runs up to the maximum number of desired activated outputs. Both values ​​are added.

The outputs are switched by two analog differential value switches and an SR element. The switching values ​​must be selected so that the direct input value and the value increased by the maximum number of outputs are set.(Q1=1 / Q1=(1+10).

The outputs are reset when no more inputs are set and the selection value is therefore 0. I have attached a demo with I1-6 / Q1-6, which you can use as a blueprint.

Regards Ella_68

(translated with google)

 Hi Ella,

Thank you for your input and appreciate your time, but this is not quite what I need.

The things are with the program you shared;

-when there is no input, there is no output. 4outputs(since you have 6 inputs in that program) should be on all the time.

-I1 should turn on Q1, I2 should turn on Q2 and goes on, until it reaches to the max number. In the program, if you turn on I5 then I4, Q4 doesn't work etc

I'll share down below what I come up with, but I can't go further to fix Max amounts of the output or when I mess with the order of inputs etc

John0196

 

Ella_68

Hello John0169,

Here is a solution:

Every input is assigned a continuous value through a chain of muxers (I1=1 ...I10=10). If an input is occupied, a counter runs up to the maximum number of desired activated outputs. Both values ​​are added.

The outputs are switched by two analog differential value switches and an SR element. The switching values ​​must be selected so that the direct input value and the value increased by the maximum number of outputs are set.(Q1=1 / Q1=(1+10).

The outputs are reset when no more inputs are set and the selection value is therefore 0. I have attached a demo with I1-6 / Q1-6, which you can use as a blueprint.

Regards Ella_68

(translated with google)

 Hi Ella,

Thank you for your input and appreciate your time, but this is not quite what I need.

The things are with the program you shared;

-when there is no input, there is no output. 4outputs(since you have 6 inputs in that program) should be on all the time.

-I1 should turn on Q1, I2 should turn on Q2 and goes on, until it reaches to the max number. In the program, if you turn on I5 then I4, Q4 doesn't work etc

I'll share down below what I come up with, but I can't go further to fix Max amounts of the output or when I mess with the order of inputs etc

A question for clarification:

Q1 to Q6 are always switched on, regardless of whether I1 to I6 are on or off ?

Q7 to Q10 may only switch on if one or more inputs from I1-I6 are switched off ?

The total number of 8 activated outputs may not be exceeded, however ? But what happens if, for example, I3 and I4 are switched off and I8 is switched off ? Should Q3 or Q4 then be switched on forcibly ?

And is there a fixed order ?

But I won't be able to deal with it until tomorrow. Now it's time for

Regards Ella_68

Ella_68

A question for clarification:

Q1 to Q6 are always switched on, regardless of whether I1 to I6 are on or off ?

Q7 to Q10 may only switch on if one or more inputs from I1-I6 are switched off ?

The total number of 8 activated outputs may not be exceeded, however ? But what happens if, for example, I3 and I4 are switched off and I8 is switched off ? Should Q3 or Q4 then be switched on forcibly ?

And is there a fixed order ?

But I won't be able to deal with it until tomorrow. Now it's time for

Regards Ella_68

 Sorry for the delay, I'll come up with the answers and better system stability. Thanks in advance!

After a little sleep and with a clear head, I'll try again.

Maybe that'll work better.

Regards Ella_68

P.S.: "Max" must always be greater than "Min"

Ella_68

After a little sleep and with a clear head, I'll try again.

Maybe that'll work better.

Regards Ella_68

P.S.: "Max" must always be greater than "Min"

 Wow! That is what I'm looking for! You are the killer, haha!

But one small note, if you turn on the last 4 inputs in order from 7 to 10, and turn off the 7; Q8, Q9 and Q10 lights up. And that's over the maximum limit. But for now, I think I got the logic and can work with that. You don't have to worry about it, for now

Hello John0169,

The error in the program has been bothering me. So I've looked into it again. This time, however, the idea was that a minimum number of outputs should be set without exceeding the maximum number. This requires a fixed order, however.

First, the number of inputs set is counted and switched through. Only then is the "filling" done with the minimum number in a fixed ascending order starting from Q1. If the "filling" reaches the maximum limit, it is interrupted. If the maximum number is exceeded when the program starts, the outputs remain off.

If the parameter values ​​"Min" and "Max" are changed during the program run, a "reset" of the circuit must be reprogrammed.

The program can easily be scaled down or expanded to the desired number of outputs.

Best wishes Ella_68