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Lathe can't cut thread well

Created by: qx100 at: 8/2/2012 10:12 AM (35 Replies)

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8/2/2012 10:12 AM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Dear experts, I meet one trouble ,our lathe (802dsl system)can't cut thread well .The first cuting is OK,but the second cuting the start position is wrong .Before the lathe never is used for cuting thread.I checked the parameter ,found the encoder parameter 31020 is 2300 ,but actual value should be 2500,that marked on the Simense encoder.I guess the pulse numbers is wrong ,so the CNC can't find the correct position when cuting thread .But when I change the 31020 to 2500 ,the feedback speed is wrong .For example ,S10 ,before abroud 10r/min,but now around 8.6 r/min.And when sp apear 360°，the the spind already run 1.26 circle.If the 31020 set to 2300,the spindle run 1.06 circlel.I also check the encoder 's fixing ,it's ok.Can you help me ?Thanks.

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8/3/2012 1:52 PM	Rate (0)
OvidiuNastac Silver Member Joined: 1/29/2008 Last visit: 7/26/2022 Posts: 419 Rating: (19)	Hi Maybe your encoder is mounted with a demultiplication ratio and they don't used MD31070 and 31080. You must see the exact ratio for the encoder or else you will not be able to do threading. What are the values for 31070 and 31080? Good luck Nit

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8/3/2012 4:08 PM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Thanks ,MD31070 and MD31080 both is 1.I also geuss encoder is mounted demultiplication ratio ,the valve around 1.3,but I can't find it.

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8/3/2012 4:31 PM	Rate (0)
CNC600 Silver Member Joined: 10/27/2009 Last visit: 3/15/2024 Posts: 455 Rating: (77)	qx100 ...MD31070 and MD31080 both is 1... Hi, please check the parameters 31050 and 31060. I guess just the parameters with index[0] are adjusted correctly. But You need to adjust the parameters with index [1] as well in the same way. Background: Below Threadcutting (G33/G331/G332) the CNC activates the parametersets for the involved Linear-Axis in the same way with the spindle axis. spindle in Gearstep#1 ==> Axis ratio in 31050/60 with index[1] becomes effective for the linear axes as well. All axis-parameters with index [0]...[5] follow this property. More details in Function description S1 (Spindel) hope that helps, CNC600
	hope that helps CNC600
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8/4/2012 6:41 AM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi,CNC600,Thanks for your help! The lathe spindle is controlled by anolog signal ,the driver is DC motor.The spindle has two gear-shift lever .MD31050 index[0]...[5] is 1;MD30160 index[0] and [1] js 85,index [3] is 21.Weare using21.Now whenrunning ,the actual speed (measured by man ) flow the setting value .But the value show on the HMI is wrong when MD31020 setting corret value (2500).Another hand ,when encoder pulse is set to 2500,the spindle turn one circle ,the spindle angle display value is more than 360°，aroud 450°.ifMD 31020 is set 2300, theSP display 390°.How to count the actual speed in CNC system? By count encoder pulse number or Z pulse number?

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8/4/2012 6:48 AM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Another question ,I got the information for manual "When cut thread ,if don't set SF ,the CNCsystem will use thread start angle SD 4200 :THREAD _START _ANGLE),"How to find the SD4200 in CNC system? I think maybe the reason is when the second cutting ,the SD4200 isn't same as first cutting's.

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8/4/2012 10:37 AM	Rate (0)
Pee El Sea Gold Member Joined: 1/19/2008 Last visit: 9/3/2025 Posts: 998 Rating: (65)	HI, It might be the phasing of your spindle encoder reference signal. When you first power up the control the spindle will not be referenced. Move the spindle by hand and look to see when the spindle referenced graphic appears or when the display resets to zero from a value other than 360. If the spindle references as soon as you move it then swap the encoder reference signal wires. Threading starts from the zero pulse or a set angle from the zero pulse. Pee

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8/4/2012 12:06 PM	Rate (0)
CNC600 Silver Member Joined: 10/27/2009 Last visit: 3/15/2024 Posts: 455 Rating: (77)	Hi, First of all You have to check the correct spindle control in each GearStep: - check the mechanical gear ratio: program M3 S60 and SPCOF and count the really effective revolutions at spindle side in each GearStep. You need to adjust 31050/60 with the mechanical assembled gearStep-Ratio to get 1 mechanical revolution in 1 sec - independend from display on HMI - check the encoder response: pending on the numbers of encoders and the interface signals to activate the encoder make sure one spindle revolution causes 360deg in display (axis diagnosis screen) usually the first encoder is located directly on the motor shaft and the second encoder is connected 1:1 to the spindle shaft. For a correct spindle response the 2nd encoder need to be declared as "direct encoder" MD ENC_IS_DIRECT[1]=1. and the ratio in 31080/90 need to be declared as the mechanical ratio of coupling - mostly 1:1. You have to check the interface signal for encoder activation as well. Do You select the first or the second encoder for position control? I'm not really sure - but the 802 provides only 1 interface signal for encoder activation. Am I right? If You want to activate the second encoder, You need to swap the encoder activation in MD 30230. To get a better overview please answer these questions: - how many encoder do You use at the spindle? - Where are the spindle related encoders assembled on? what ratio? - where did You define the encoder data now - encoder dataset [0] or [1]? result of Your first cutting: - does the pitch of thread match to the programmed value? hope that helps CNC600
	hope that helps CNC600
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8/4/2012 4:45 PM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi,CNC600,thanks for your help! Below is my answer 1、the spindle is analog cotrolled.Spindlemotor is DC motor ,and driver is 6RA70.Motor speed feedback is by tachogenerator. 2.Spindle encoder on the spindle box,MD31070 and MD31080 is 1:1.MD31040 is 1. 3.because we only use one encoder ,we only fill encoder pulse number in the MD31020 . 4.The first cutting is ok,but the start position is wrong when second cycle begin.And pitch of thread of first cutting is OK.

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8/4/2012 5:54 PM	Rate (0)
CNC600 Silver Member Joined: 10/27/2009 Last visit: 3/15/2024 Posts: 455 Rating: (77)	Hi, if the MD 31070/80 and 31040 are below index [0] - the setting in the MD's is OK. the pitch of the first cut is also (almost?) OK. But in the MD31020 ENC_RESOL belongs 2500 (I believe Your investigation regarding the assembled direct encoder). The problem occurs out of the encoder configuration on the SINAMICS side. For a further investigation a couple of information is needed about the SINAMICS configuration. As I know the spindle encoder is attached at a SMC20-Modul. Internaly the encoder values will be transferred parallel to any other axis encoder signals in an unused 2nd encoder channel. Now we want to find out the channel of transpotation of the encoder signals: what is inside in 30220 [0] and 30220 [1] of the spindle NC-MD's? (ENC_MODULE_NR) I guess You'll find the same number in MD 30220 in any other linear axis – What axis? Where did they connect the encoder cable from the spindle encoder? to a SMC20-Module? Hope that helps CNC600
	hope that helps CNC600
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8/4/2012 6:40 PM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi, The spindle encoder is attached X axis .MD30220 is 1.Yes ,the encoder cable connectspindle encoder and SMC 20 Module.

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8/4/2012 7:11 PM	Rate (1)
CNC600 Silver Member Joined: 10/27/2009 Last visit: 3/15/2024 Posts: 455 Rating: (77)	OK, please check the SINAMICS DriveData: (The encoder data for the spindle are stored from p0400[1]) The encoder type is declared on the SINAMICS side in p0400[1]: What's inside now? if p0400[1]=9999 what's inside in p0404[1] (encodertype) and p0408[1] (numer of enc pulses) and p0425[1] (zero pulse distance) hope that helps CNC600
	hope that helps CNC600
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This contribution was helpful to 1 thankful Users Ekalavya

8/5/2012 12:18 PM	Rate (0)
CNC600 Silver Member Joined: 10/27/2009 Last visit: 3/15/2024 Posts: 455 Rating: (77)	Hi again, to accelerate this Q&A-game I want to explain some basics of a correct spindle setting: 1. commissioning/check the encoder esponse 2. commissioning/check the spindle control to the 1st item: need to check the encode coupling on the spindle shaft: MD31040 ENC_IS_DIRECT, MD31070, MD31080 ENC-Ratio MD31020 ENC_RESOL Anyway these MD's have to be set correctly. You can check this by moving the spindle exact 1 revolution and monitor the moving distance in the diagnosis screen ==> 360deg are needed. currently 31040, 31070, 31080 seem OK, but 31020 need to be set on 2500 (encoder with 2500pulses). The correct encoder response is a basic for a correct result in thread cutting. to the 2nd item: The spindle control is independing from the used direct encoder (in SPCOF-mode)! basically the spindel control is related only to these three parts: - setpoint calculation in CNC - setpoint to speed connection in the motorcontroler - mechanically gear ratio from motor to the spindle head setpoint calculation: the CNC controls the setpoint out of following parameters: MD 31050, MD31060 (really mechanically rear ratio needed) MD 32250, RATED_OUTVAL MD 32260 RATED_VELO MD 35130 GEAR_STEP_MAX_VELO_LIMIT speed controler: during the commissioninh the 6RAxx has been set to generate a motor speed related to a sepoint value. (e.g 3000rpm at 10V) This setting is related to the motor and a lot of mechanical & electrical circumstances. gear ratio: the gearbox transfers the motorspeed to the spindle speed. ############### out of You previous information: when 31020 = 2500 ==> the spindle speed is not OK anymore (approx 12,5rpm instead of 10rpm) I guess: the spindle controler is optimized to 8V for max motor speed, but the CNC calculates 10V for max motor speed. (eg MD32250= 100%) so the drive controller always get 1,25*setpoint. Try to correct the spindle speed by adjusting MD32250 from 100% to 80%. If You need further support, post all the parameter adjustments I wrote above and additionally the values out of a constant spindle run: - M3 S50 (approx 10% of max spindle speed programmed) - measure the setpoint in Volt (CNC output or controler input) - measure the really motor speed (direct at the motor shaft or from parameter in 6RAxx) - read the spindle speed from HMI ##################### on the other hand: Why the machine manufacturer delivered such a useless setting? What maxchine type and manufactuere is this? hope that helps CNC600
	hope that helps CNC600
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8/5/2012 3:42 PM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi, Just I check the parameter form by STARTER,as below P0400[0]=2001 p0400[1]=9999 P0400[2]=9999 P0404[0]=109030H P0404[1]=102011H P0404[2]=101010H P0408[0]=2048 P0408[1]=2048 P0408[2]=2500 P0425[0]=2048 P0425[1]=2048 P0425[2]=2500

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8/5/2012 4:14 PM	Rate (0)
CNC600 Silver Member Joined: 10/27/2009 Last visit: 3/15/2024 Posts: 455 Rating: (77)	OK, inside the SINAMICS the spindle encoder has been defined with 2500 pulses, reference pulse detection is active. ==> looks fine. next step: axis MD (spindle): 31020 ENC_RESOL = 2500 and check the spindle encoder response in diagnostic screen: 1rev = 360degree? hope that helps CNC600
	hope that helps CNC600
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8/5/2012 4:34 PM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi, Now,I introduce the commissioningresultthat I do before. M3 S10 ,.......the 6RA70 input (MCPA output)and tachogenerator feedback(3000rpm =10V), is almost same.(MD32260=2400) And actual speed that measure by man is almost 10rpm. 1.if MD31020 is 2300,1 revolutionaround 360°,and feedback speed that display oneHMI is almost 10 rpm. 2.if MD31020 is 2500 ,1 revolution around 270°,and feedback speed that display on HMI is around 8.6rpm.

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8/5/2012 4:45 PM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi, Sorry ,if MD310220=2300,1 rev=330 degree.

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8/5/2012 5:04 PM	Rate (0)
CNC600 Silver Member Joined: 10/27/2009 Last visit: 3/15/2024 Posts: 455 Rating: (77)	qx100 Hi, Now,I introduce the commissioningresultthat I do before. M3 S10 ,.......the 6RA70 input (MCPA output)and tachogenerator feedback(3000rpm =10V), is almost same.(MD32260=2400) And actual speed that measure by man is almost 10rpm. 1.if MD31020 is 2300,1 revolutionaround 360° 2.if MD31020 is 2500 ,1 revolution around 270° I cannot understand this result. Did You execute a PowerOn after changing the MD31020? The CNC just count the pulses during one revolution ==> more pulses - longer distance displayed! 10rpm at motor shaft and 10 rpm at spindle side and a gear ratio with approx 1/80 or 1/20??? Your result does not match to my experince... Please trry again: 31020 to 2500 ==> PowerOff-PowerOn (Or NCKRESET) and move the spindle manually about 1 rev. ==> how many degrees difference will be displayed in the diag screen? hope that helps CNC600
	hope that helps CNC600
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8/5/2012 5:22 PM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi,Sir, I also can't understand it. I ensure to restart CNC after changing MD31020(poparameter). I adjust theMD31020 to 2260,now1 rev almost 360 degree.10 rpm is spindle speed.

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8/5/2012 5:41 PM	Rate (0)
CNC600 Silver Member Joined: 10/27/2009 Last visit: 3/15/2024 Posts: 455 Rating: (77)	qx100 ..MD31020 to 2260,now1 rev almost 360 degree.,, This is not possible.... Are You sure the ratio from spindle head to the spindle encoder is really 1:1 (MD31070 31080)? There is no other chance to adjust the direct encoder. MD31020 = 2500 and 1rev is 360degree. MD30330 need to be on 360deg. Right? hope that helps CNC600
	hope that helps CNC600
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8/6/2012 2:57 AM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi, I am surethe ratia from spindle head to spindle encoder is really 1:1(MD30170 and MD31080 both is 1).Spindle encoder shaft is connected the spindle shaft directly ,no any other adjustment between them.And I check MD30330 is really 360 degree. I also check the spindle encoder's connection ,it's OK. Maybe there some trouble with spindle encoder .

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8/6/2012 7:09 AM	Rate (0)
OvidiuNastac Silver Member Joined: 1/29/2008 Last visit: 7/26/2022 Posts: 419 Rating: (19)	qx100 Thanks ,MD31070 and MD31080 both is 1.I also geuss encoder is mounted demultiplication ratio ,the valve around 1.3,but I can't find it. qx100 Hi, I am surethe ratia from spindle head to spindle encoder is really 1:1(MD30170 and MD31080 both is 1).Spindle encoder shaft is connected the spindle shaft directly ,no any other adjustment between them.And I check MD30330 is really 360 degree. I also check the spindle encoder's connection ,it's OK. Maybe there some trouble with spindle encoder . Hi What is the correct answer? First or second one? The only reasonable cause for the difference between the real number of the encoder pulses and the one that you have in MD's is that you have a gear between the encoder and the spindle. Another cause for incorrect treading could be the gear between the motor and the spindle. You must fill the MD's for all the axes for all the indices [0], [1], [2] even if you don't have any gear for the other axis. Good luck Nit
	Last edited by: Nit at: 8/6/2012 12:38 PM
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8/6/2012 11:22 AM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi, I am sure no any gear between spindle encoder and spindle shaft ,see picture.And ,the MD30150 ,MD31060 index[0]...[5],have fill the data. Attachment encoder connection.jpg (220 Downloads)

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8/8/2012 7:10 AM	Rate (0)
CNC600 Silver Member Joined: 10/27/2009 Last visit: 3/15/2024 Posts: 455 Rating: (77)	Hi, what's inside in MD 31064 DRIVE_AX_RATIO2_DENOM and 31066 DRIVE_AX_RATIO2_NUMERA? Anyway before we can find the problem with the spindle speed deviation we have to adjust: ==> 1really revolution on spindle side causes360deg position deviation in diagnostic screen. The encoder deliveres 1 zero pulse per revolution, the CNC calculates with 2500 pulses per revolution (defined in 31020). Additionally the CNC deliveres different values after modification of MD31020 (encoder assignment is OK). Although the spindle speed is not correct yet (difference in GearRatio or missetting in SetPoint calculation) - the thread must be OK. The CNC pickup the really spindle speed only from encoder signal! Can You provide us an archive with all machine parameters? hope that helps CNC600
	hope that helps CNC600
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8/8/2012 11:36 AM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi, Thank you for your help!Attached is the parameter. Best Regards Attachment 802D DATA.zip (235 Downloads)

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8/9/2012 4:44 AM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi, Starter parameter(configuration ) Attachment Startr parameter .zip (250 Downloads)

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8/10/2012 5:09 PM	Rate (0)
CNC600 Silver Member Joined: 10/27/2009 Last visit: 3/15/2024 Posts: 455 Rating: (77)	P0400[0]=2001 p0400[1]=9999 P0400[2]=9999 P0404[0]=109030H P0404[1]=102011H P0404[2]=101010H P0408[0]=2048 P0408[1]=2048 P0408[2]=2500 P0425[0]=2048 P0425[1]=2048 P0425[2]=2500 Hi, You configured the spindle encoder as a 3rd encoder in the SINAMICS in the X-Servo. The drive communication protocol transfers max. only two encoder data streams. Therefore the direct encoder of X-Axis has been set: N30110 $MA_CTRLOUT_MODULE_NR[0,AX1]=1 ; 1st module N30130 $MA_CTRLOUT_TYPE[0,AX1]=1 N30220 $MA_ENC_MODULE_NR[0,AX1]=1 ; X-Servo N30230 $MA_ENC_INPUT_NR[0,AX1]=2 ; 2nd encoder on DBX1.5 in PLC The Spindle encoder setting: N30110 $MA_CTRLOUT_MODULE_NR[0,AX3]=3 ; 3rd module N30130 $MA_CTRLOUT_TYPE[0,AX3]=1 N30220 $MA_ENC_MODULE_NR[0,AX3]=1 ; X-Servo! N30230 $MA_ENC_INPUT_NR[0,AX3]=not defined in the MD, standard is 1 ==> so the SINAMICS need to transfer the 3rd encoder into the 1st protocol in the X-Servo. I cannot debug this out of the existing data (no equipment available). I hope. somebody assigned the encoder correctly... Thespindle encoder setting is still on 2300:, but 2500 is IMHO requested N31020 $MA_ENC_RESOL[0,AX3]=2300 This parameter is useless for a incremental encoder: N31025 $MA_ENC_PULSE_MULT[0,AX3]=2300 Spindle speed settings: N31060 $MA_DRIVE_AX_RATIO_NUMERA[0,AX3]=85 N31060 $MA_DRIVE_AX_RATIO_NUMERA[1,AX3]=85 N31060 $MA_DRIVE_AX_RATIO_NUMERA[2,AX3]=21 Gear ratio is 1/85 or 1/21 N32250 $MA_RATED_OUTVAL[0,AX3]=100 N32260 $MA_RATED_VELO[0,AX3]=2400 The CNC provides a motor speed of 2400rpm at 100% setpoint (10V) the maximum gear velo requires following motor speed N35130 $MA_GEAR_STEP_MAX_VELO_LIMIT[0,AX3]=32 ==> requires 3281 = 2591rpm N35130 $MA_GEAR_STEP_MAX_VELO_LIMIT[1,AX3]=32 N35130 $MA_GEAR_STEP_MAX_VELO_LIMIT[2,AX3]=126==> requires 12621 = 2646rpm The setting of 32250 and 32260 does not match to this calculation. Obviously, a different controler adjustment in the 6RAxx might compensate this setting. Although -I keep my suggestion: modify 31020 to 2500 to get 360deg for 1 real spindle revolution. hope that helps, CNC600
	hope that helps CNC600
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8/11/2012 2:50 AM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi, Now ,the lathe is OK! We ask one company come to fix the issure .The service people change MD34040 from 0.83333 to 5 and change 35300[0]...[5] from 500 to 10 ,last change MD31020 from 2300 to 2500 ,after restarting CNC ,It's OK! Now speed that display on screen is ok,and 1 real revolution is 360 degree.And cut thread is well now . I check the MD35300 ,manual mentioned it can't exceed MD35135 ,if MD35135 is 0, then the value is limitted 90% MD35130 .Before MD35135 =0,MD35130 is 32 ,but MD3500 is 500 ,it exceed the 90%*MD35130(32)=28.8.But the service people do't tell me the reason .CNC600 can you help me to explain it? Thanks very much for help some many days . Best Regards.

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8/11/2012 7:35 AM	Rate (0)
CNC600 Silver Member Joined: 10/27/2009 Last visit: 3/15/2024 Posts: 455 Rating: (77)	Hi, the final reason for the success was the modification MD31020 from 2300 to 2500.Only this MD is responsable for the correct spindle feedback (in Your configuration). The modification MD35300[0]...[5] from 500 to 10 is related to the SPOS command (M19), This parameter defines the speed for switching on the position controler when SPOS in programmed and the spindle is not on reference yet. 500 rpm was too high before. (more than max speed). The modification MD34040 REFP_VELO_SEARCH_MARKER from 0.83333 to 5 is a reference issue, defines the speed for zero puls searching. (causes just a shorting of referencing time). regarding the 90%-limitation: the CNC limits internally the speed setpoint for the spindle on 90% of the available max speed when the spindle's position controller has been switched on (e.g. SPCON, after SPOS/M19...). The "available max speed" is a result of an internal calculation of many parameters. One of them is MD35135. MD35135 = 0 ==> 90% limitation is active in SPCON MD35135 <> 0 ==> the limitation of MD35135 becomes effective in SPCON. hope that helps CNC600
	hope that helps CNC600
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8/11/2012 8:26 AM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi, I don't understand why before changing the MD35300 and MD34040 ,I set MD31020 to 2500 ,the speed that display on screen(set 10 rpm ,actual value is 8.5 rpm)and the 1 revolution is about 270 degree. Best Regards

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8/11/2012 10:18 AM	Rate (0)
CNC600 Silver Member Joined: 10/27/2009 Last visit: 3/15/2024 Posts: 455 Rating: (77)	qx100 Hi, I don't understand why before changing the MD35300 and MD34040... I do not understand as well... I do not have any explanation for the connection of MD 35300 and MD34040 with a misconfiguration in encoder response. The only possible explanation would be, the test (movement of spindle) has been executed with active SPCON by a CNC-command. e.g. POS[C]=IC(360) and not by a simple movement by hand. hope that helps CNC600
	hope that helps CNC600
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8/22/2012 6:11 PM	Rate (0)
GOTHIC HERO Regular Member Joined: 9/30/2011 Last visit: 6/20/2021 Posts: 28 Rating: (0)	Hello, Please check the parameter MD31040,it should be 1.

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6/27/2014 11:48 AM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	Hi,CNC600, Thank you for your help before ,but now ,the fault happened again .The operator restore the system by "start by saved data",the parameter is reset to primary data.The fault happened again ,but when I changed the encoder pulse from 2300 to 2500 ,and changed the MD34040 from 0.83333 to 5 and change 35300[0]...[5] from 500 to 10 ,follow service people done ,but no any help ,maybe l don't record whole changed parameter .Now I revolution only 296 degree! I think it's as before .I don't understand which paramter is wrong ? Can you help me ? Thanks! (31070 =31080=1,30330 =360 ,30242-0,detail parameter see above attached in thread.)

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6/29/2014 12:31 PM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	I find MD30230 =1,but according manual MD0230=2 ，which is correct? or both is OK?

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7/1/2014 11:44 AM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	I have checked ,if MD30230 =2 ,then spindle no any signal .

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7/16/2014 10:06 AM	Rate (0)
qx100 Advanced Member Joined: 1/12/2011 Last visit: 6/19/2025 Posts: 46 Rating: (0)	I have found the reason .Though it's so easy ,but the progress is ....... .。The MD31070 and 31080 is setted wrong value.When I havechecked all the parameters ,suddenly ,I understand maybe I made one mistake at first .Though the spindle encoder is directly installed on spindle headbox ,not found gear reducer,so I think MD31070 and 31080 should be both is 1.When I set MD31070 to 5,s1080 to 6,everything is OK.So I thanks a lot for CNC600 and other experts!

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