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network design output control

Created by: AutoGen_5000602 at: 2/1/2024 6:44 AM (14 Replies)

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2/1/2024 6:44 AM	Rate (0)
AutoGen_5000602 Joined: 1/2/2023 Last visit: 7/10/2025 Posts: 14 Rating: (0)	1-when controlling output q1 in logo/192.168.0.2/ via network output nq2/192.168.0.2/, the red operation indication q1-test in simulation does not appear 2-if the project contains the graphic symbol q1, then vb1064.0 is 0 Attachment logo1.jpg (390 Downloads)

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2/1/2024 6:49 AM	Rate (0)
ixo65 Grandmaster Joined: 12/18/2014 Last visit: 9/15/2025 Posts: 35961 Rating: (4502)	If an output (Q1 in your case) in the diagram on the input side is connected to logic, this output cannot be switched remotely. Bit V1064.0 is only an image of the state of Q1 and is not used for switching, but only for display.

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2/1/2024 7:23 AM	Rate (0)
AutoGen_5000602 Joined: 1/2/2023 Last visit: 7/10/2025 Posts: 14 Rating: (0)	3 - if we remove the q1 symbol in the project, the table shows the correct situation v1064.0=1 4-if we remove the q1 symbol in the project, the table shows the correct situation v1064.0=1 why is this happening? where is the mistake? Attachment logo4.jpg (378 Downloads)
	Last edited by: AutoGen_5000602 at: 02/01/2024 16:38:50
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2/1/2024 7:25 AM	Rate (0)
ixo65 Grandmaster Joined: 12/18/2014 Last visit: 9/15/2025 Posts: 35961 Rating: (4502)	AutoGen_5000602 3 - jeśli usuniemy w projekcie symbol q1, tabela pokazuje prawidłową sytuację v1064.0=1 [snip] ???

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2/1/2024 8:11 AM	Rate (0)
qwazee Platinum Member Joined: 3/30/2020 Last visit: 9/15/2025 Posts: 5447 Rating: (1064)	The way Q3 is connected in the right hand project is correct. The output is not meant to be manipulated directly without making any program connection. Not connecting to Q1 in the right hand project is not the prescribed way of working. The representation of the inputs/outputs in the V-memory is read only. The V-memory does not meant override the inputs/outputs as you wish for. There is the possibility of making a LOGO a slave device. Then the LOGO does not contain a program. It is then only a terminal for remote inputs/outputs. Would this suit your situation better?
	Activities of this user is voluntary. There is no obligation or liability placed on this user. Though optional, your 'please' and 'thank you' is highly valued.
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2/1/2024 8:20 AM	Rate (0)
ixo65 Grandmaster Joined: 12/18/2014 Last visit: 9/15/2025 Posts: 35961 Rating: (4502)	AutoGen_5000602 [snip] 4-if we remove the q1 symbol in the project, the table shows the correct situation v1064.0=1 why is this happening? where is the mistake? Because you are working in the simulation and not in a real LOGO!.

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This contribution was helpful to 1 thankful Users qwazee

2/1/2024 12:23 PM	Rate (0)
Jen_Moderator Diamond Member Joined: 6/19/2017 Last visit: 9/6/2024 Posts: 8171 Rating: (174)	AutoGen_5000602 3 - jeśli usuniemy w projekcie symbol q1, tabela pokazuje prawidłową sytuację v1064.0=1 4-if we remove the q1 symbol in the project, the table shows the correct situation v1064.0=1 why is this happening? where is the mistake? Hello AutoGen_5000602, Please try to discuss your question in English language. This is an international community, and we try to focus on one language. Posting in English will help you to get more response to your question. This is the translation of your post: AutoGen_5000602 3 - if we remove the q1 symbol in the project, the table shows the correct situation v1064.0=1 4-if we remove the q1 symbol in the project, the table shows the correct situation v1064.0=1 why is this happening? where is the mistake? Regards, Jen_Moderator

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2/1/2024 4:39 PM	Rate (0)
AutoGen_5000602 Joined: 1/2/2023 Last visit: 7/10/2025 Posts: 14 Rating: (0)	sorry, I corrected it

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This contribution was helpful to 1 thankful Users Jen_Moderator

2/1/2024 4:56 PM	Rate (0)
AutoGen_5000602 Joined: 1/2/2023 Last visit: 7/10/2025 Posts: 14 Rating: (0)	vm bit table shows that bit vb1024.0 was set =1 if the diagram on the right side did not contain outq1 this experiment conflicts with your thesis that byte vb1024 is only an image and cannot be written also in the ethernet output menu there is an item q What do you think? Attachment IMG_0448.JPG (343 Downloads)

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2/1/2024 5:05 PM	Rate (0)
ixo65 Grandmaster Joined: 12/18/2014 Last visit: 9/15/2025 Posts: 35961 Rating: (4502)	I think that you don't want to accept that you cannot write to this memory area in a real LOGO, only the operating system of the LOGO! can do that. If you have a different opinion, please feel free to do so. But then don't be surprised if I don't answer anymore.

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2/1/2024 6:03 PM	Rate (0)
ixo65 Grandmaster Joined: 12/18/2014 Last visit: 9/15/2025 Posts: 35961 Rating: (4502)	AutoGen_5000602 [snip] also in the ethernet output menu there is an item q [snip] I think that the variable Q in select menu of a NQ is for the case that you have a Master/Slave connection, not a Master/Master connection (Client/Server). By a Master/Slave connection is one LOGO! the master, the other LOGO! is the slave. This LOGO! must to in slave mode. Tools > Transfer > Configure Master/Slave mode The slave LOGO! is then "dumb", has no program. It provides the master LOGO! with its hardware. From master then you can switch e.g. Q1 via NQ.

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2/1/2024 6:15 PM	Rate (0)
ixo65 Grandmaster Joined: 12/18/2014 Last visit: 9/15/2025 Posts: 35961 Rating: (4502)	See also this application example from Siemens Building Automation: House Control with LOGO! 8 and Master-Slave Communication (LOGO! Set 9)

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This contribution was helpful to 1 thankful Users qwazee

2/4/2024 7:41 PM	Rate (0)
AutoGen_5000602 Joined: 1/2/2023 Last visit: 7/10/2025 Posts: 14 Rating: (0)	You're right really you cannot enter the address v102//4// in the internet smoking menu Attachment IMG_0456 zm1.jpg (298 Downloads)
	Last edited by: Jen_Moderator at: 02/05/2024 12:31:16 Text formatting optimized.
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2/4/2024 7:57 PM	Rate (0)
AutoGen_5000602 Joined: 1/2/2023 Last visit: 7/10/2025 Posts: 14 Rating: (0)	ixo65 great advice this means that you can control the outputs when the logo is a client and does not contain a program Attachment IMG_0457zm1.jpg (332 Downloads)
	Last edited by: AutoGen_5000602 at: 02/04/2024 20:00:29 Last edited by: Jen_Moderator at: 02/05/2024 12:31:47 Text formatting optimized.
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2/5/2024 3:47 AM	Rate (0)
ixo65 Grandmaster Joined: 12/18/2014 Last visit: 9/15/2025 Posts: 35961 Rating: (4502)	Why? If the second LOGO! is also a client but does not contain a program, how is that supposed to work? Either you do the master/slave procedure, then the master controls the outputs of the slave LOGO! and reads the inputs of the slave LOGO!. In this case the slave LOGO is "dumb" and has no program. Or you do the master/master procedure, then one LOGO! is the client and the other LOGO! is the server. Both LOGO!s then have a program.
	Last edited by: ixo65 at: 02/05/2024 03:49:06
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