iad

It's actually not so difficult math and even windows calculator can calculate (-3)^3

Right now I'm calculating this by x*x*x but it would look much better with x^3 and I don't think it is so difficult to implement the negative numbers in the power operator.

You are right,I was talking about the real number such as (-1.2)^(-1.2).For such a cases,They do not have direct solution.They don't support (X^N) in general.If you check samples in online manuals or Books published officially by SIEMENS,They recommend using Mathematics with basic available instructions (such as EXP,LN,SIN,COS) to make complex math functions.

Pegaia

Hi,

is in your case to use fractionary power numbers (for example -2^3,5), or you would be satisfied with integer power number (-2^³)?
Is the power number a constant or a variable?

As work around, for x<>0 and y as integer, you can use:

x^y = (abs(x))^y * (abs(x)/x)

iad

We are going for a simillar solution as Pagaia is suggesting since we are using only constant positive integer powers and thus avoiding complex numbers

I havn't had enough time to go through your solution hdhosseini since my problem is "too easy" to include complex math . But if i remember correct that was the way to go when calculating fractional power of a negative numbers. Who knows maybe we'll get use of it in the future

Thanks for a good discussion!

Hi,

sorry for my replay,

this work at 100% with + and - in awl?

Thank you in advace

hdhosseini

iad

We are going for a simillar solution as Pagaia is suggesting since we are using only constant positive integer powers and thus avoiding complex numbers

I havn't had enough time to go through your solution hdhosseinisince my problem is "too easy" to include complex math. But if i remember correct that was the way to go when calculating fractional power of a negative numbers. Who knows maybe we'll get use of it in the future

Thanks for a good discussion!

Hello friends,

Thank you for all contributions.We reached to a conclusion after all discussions.I also prefer Pagaia's solution for INT as the snapshot suggests.

Topic discussed in very details and has some positive point for me and this was why I asked the moderators to mark it "Highlight".Stars from me (as soon as I have some to give) for all positive attitudes.

Thank you for theBESTthread I have contributed during the campaign
Hamid Hosseini 

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Split from Calculation problem taking power of a negative number.