Contactor breaking capacity

Greetings....

Could you please help to resolve the matter,

For 4.00KW motor DOL protection, as per type-2 below breaker and contractor combination are used, 

The contactor used is 3RT2024 with 12 A nominal current and the assumed breaking capability is 8 x 12 = 96 A. Its minimum drop-out time is 0.014 sec (0.004 sec opening delay + 0.01 sec arcing time). In the attached time-current protection curve of this motor, the point (96 A, 0.014 sec) is shown. The breaker used is 3RV2321 of In = 10 A and instantaneous trip = 130 A. The instantaneous trip has a +/-20% tolerance which gives an upper band at 156 A.For any overcurrent between the contactor breaking capability of 96 A and the instantaneous trip upper band of 156 A, the 49 protection (Simocode) will trip the circuit via the contactor but the contactor breaking capability will be exceeded.

There is a risk of the contactor being destroyed by trying to break an overcurrent which it is above its breaking capability.

Try of opening of contactor with higher currents than the contactor breaking capacity can destroy the contactor ?