9/5/2019 1:54 PM  
Joined: 8/24/2010 Last visit: 12/8/2023 Posts: 23 Rating: (1) 
Hello Siwarexi, [snip] Do you know also how to calculate the accuracy of the siwarex card WP321? I found this : d(min(ND))= Delta u min x Emax x N / C / Uexc C is mV/V of the loadcell I guess... What do you think about this calculation?  
Last edited by: Jen_Moderator at: 09/06/2019 09:06:45New subject after splitting. Division of questions into seperate topics. 

9/9/2019 9:40 AM  
Joined: 1/4/2007 Last visit: 12/8/2023 Posts: 1071 Rating: (165)

Hello monkeyjacob, To calculate the accuracy of the WP321 together with load cells, I need to know:  the technical data sheet of the load cells  the nominal load of the load cells  the number of load cells Your calculation regarding the Siwarex WP321 is correct . Best regards Siwarexi 
Last edited by: Siwarexi at: 09/09/2019 09:43:28 

9/12/2019 11:35 AM  
Joined: 8/24/2010 Last visit: 12/8/2023 Posts: 23 Rating: (1) 
Hi Siwarexi, Thanks for you answer ;) Herewith the can find the datasheet of the loadcell : http://www.weightech.com.br/datasheet/hbmz6fc3datasheetb1010v3.pdf Model > Z6FC3 with nominal load of 50kg. The scale can be use until 60kg (written on the scale) There is only one loadcell. Let me know if you need something else ;) Monkeyjacob 
9/13/2019 10:08 AM  
Joined: 1/4/2007 Last visit: 12/8/2023 Posts: 1071 Rating: (165)

Hello monkeyjacob, You will reach an accuracy of 5gr with the Siwarex WP321 module and one load cell. Best regards Siwarexi 
9/13/2019 10:57 AM  
Joined: 8/24/2010 Last visit: 12/8/2023 Posts: 23 Rating: (1) 
Hello Siwarexi, I found another accuracy for this application : Loadcell = (50 x (1)^1/2) / 3000 = 0,016 kg = 16 gr Emax= 50kg Nb loadcell = 1 Y = 3000 Siwarex card = (0,5 * 50 * 1) / (2 x 4,85) = 2,57 gr Could you tell what you did? Thanks a lot, Monkeyjacob 
9/13/2019 1:08 PM  
Joined: 1/4/2007 Last visit: 12/8/2023 Posts: 1071 Rating: (165)

Hello monkeyjacob, Loadcell = (50 x (1)^1/2) /3000???= 0,016 kg = 16 gr Emax= 50kg Nb loadcell = 1 Y = 3000 ??? => Y = 11111 MY CALCULATION IS: Loadcell = (50 x (1)^1/2) / 11111 = 4.5 gr =5 gr Siwarex card = (0,5 * 50 * 1) / (2 x 4,85) = 2,57 gr Yes, here you are right. I also got ths value. Now, you have to use the higher value from the calculations: 5 gr and 2.57 gr. The higher value is 5 gr. Therefore the accuracy of your whole scale is 5 gr. Best regards Siwarexi 
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9/13/2019 2:01 PM  
Joined: 8/24/2010 Last visit: 12/8/2023 Posts: 23 Rating: (1) 
OK I've fully understood now. For Y I used the parameter nLC = 3000 on the top of the datasheet. I thought it was the Y parameter. Thank you for your support Monkeyjacob 
Last edited by: monkeyjacob at: 09/13/2019 14:02:10 

12/29/2020 5:35 AM  
Posts: 84 Rating: (19) 
Hi Siwarexi, can you explain on the bellow formula to calculate the accuracy. On the below calculation 50 = loadcell capacity (1) = no. of loadcell ^1/2 = ? 11111 = ? Also on Siwarex is the 0.5 = Step voltage 0.5 µV/e? 50 = loadcell capacity / nominal load ? 1 = ? 2 = ? 4.85 = ? MY CALCULATION IS: Loadcell = (50 x (1)^1/2) /11111= 4.5 gr =5 gr Siwarex card = (0,5 * 50 * 1) / (2 x 4,85) = 2,57 gr

1/7/2021 5:54 PM  
Joined: 1/4/2007 Last visit: 12/8/2023 Posts: 1071 Rating: (165)

Hello subin, To calculate the accuracy, I need the technical data sheet of the load cell. Best regards Siwarexi

1/8/2021 2:42 PM  
Posts: 84 Rating: (19) 
Hi Siwarexi, I just need to understand the formula based on the datasheet of the loadcell discussed here. Loadcell = (50 x (1)^1/2) /11111= 4.5 gr =5 gr Siwarex card = (0,5 * 50 * 1) / (2 x 4,85) = 2,57 gr Please can you explain each parameters in the above formula. Regards, Subin Sam Mathew 
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