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2/14/2014 4:24 AM | |
Joined: 8/25/2006 Last visit: 10/18/2024 Posts: 2209 Rating: (279) |
Hello. If you talk about 6RA70:
Look at themanual, chapter 8 'Function diagrams', sheet B115. Here you will find F023 (function block 2, 2 inside ellipse). You can see that the sources of F023 could be in parameter U100.01...U100.04. There could be binector numbers. Then goto Binector list (chapter 12.2 of the manual), find required binector here. Let's say, e.g., this are B0010 and B0040, at the right column you will see the sheet number oа function diagram (G110 and G186 in this example). Open this sheets and you can see from where this binary signal comes. |
Last edited by: KSN at: 2/14/2014 4:33 AM |
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This contribution was helpful to1 thankful Users |
2/14/2014 3:21 PM | |
Posts: 3 Rating: (0) |
Thanks KSN! Now is clear! Excellent! |
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