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S7 Graph - Activate Step Between Sequencers

Created by: hshen-sync at: 6/6/2013 10:32 AM (6 Replies)

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6/6/2013 10:32 AM	Rate (0)
hshen-sync Posts: 18 Rating: (1)	Dear Experts I have created a test graph FB with two sequencers. Sequencer 1 has two steps(including the intial step) and Sequencer 2 has 1 step. I am trying to use the event dependent actions - "S1 On" in step 1 inside Sequencer 1(Main Sequencer) to activate a step in Sequencer 2(sub Sequencer). Step 1 in Sequencer 2 should start timing and once the time exceeds 3s. Step 2 in Sequencer 1 should be activated, after step 2 timing past 4s, then the sequence should jump back to step 1 in sequencer 1. As soon as I enable the FB, Initial Step in Sequencer 1 is activated and timing. But step 1 in sequencer 2 is never activated. Am I doing something wrong here? Can I use this instruction? The reason I am doing it this way is for the structure of the code. So the Main Sequencer acts as the main routine and the sub sequencers act as sub-routines. Thank you in advance.
hshen-sync Posts: 18 Rating: (1)
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6/11/2013 11:10 AM	Rate (1)
Kampi Posts: 366 Rating: (30)	Hi, when i understand you exactly: Step-1 in sequencer-1 should activate Step-1 in sequencer-2. After Step-1 in sequencer-2 is activated for 3 sec, step-2 in sequencer-1 should be activated. After step-2 in sequencer-1 is activated for 4 sec, step-1 in sequencer-1 should be activated again. So with Step-1 in sequencer-1 you set a marker (for example M100.0). This Marker is the transition to activate Step-1 in sequencer-2 so you need to put it on FB-Graph input "INIT_SQ". Also put the M100.0 in the Interlock-transition of Step-1 sequencer-2. Transition for Step-2 in sequencer-1 is a timer (T100) which is setted by M100.1. This Marker M100.1 is setted by Step-1 in sequencer-2 (on-delay 3sec). And after Step-2 in sequencer-1 is activated M101.0 is setted and M100.0 is reseted. M101.0 activates T101 (on-delay 4sec). T101 is the transition to jump back in step-1 sequencer-1. Please look at the code in attachment! I hope this helps you. nice regards Attachment Sequencer1.pdf (529 Downloads)
Kampi Posts: 366 Rating: (30)
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6/11/2013 11:10 AM	Rate (0)
Kampi Posts: 366 Rating: (30)	Also this attachment! Attachment Sequencer2.pdf (394 Downloads)
Kampi Posts: 366 Rating: (30)
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6/11/2013 11:11 AM	Rate (0)
Kampi Posts: 366 Rating: (30)	And this! Attachment Overview.pdf (420 Downloads)
Kampi Posts: 366 Rating: (30)
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6/18/2013 10:32 AM	Rate (0)
hshen-sync Posts: 18 Rating: (1)	Hi Kampi Thank you for the reply. I have managed to solve my problem. I have attached my test Graph code here so that it may help other people. Here are some tips I found out. 1. cannot use event dependent actions for the Initial Step. This step is required in order for the system to return to the start of a sequencer. 2. it is not a good programming practise to use jump between two sequencers. The jump instruction bypass the transition to the step it jumps into. Thus the previous step will not be disabled and is activated all the time. So instead of using jump instruction from Sequencer 2 to Sequencer 1, I have inserted a stop at end of Sequencer 2 and set the bit M200.2 which is part of the transition to Step 3 in Sequencer 1. It is a silly mistake I made. Hope everyone can learn from it. Attachment S7 Test Seqencer 1.pdf (414 Downloads)
hshen-sync Posts: 18 Rating: (1)
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6/18/2013 10:32 AM	Rate (0)
hshen-sync Posts: 18 Rating: (1)	Sequencer 2. Attachment S7 Test Sequencer 2.pdf (254 Downloads)
hshen-sync Posts: 18 Rating: (1)
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7/15/2013 12:14 PM	Rate (0)
Kampi Posts: 366 Rating: (30)	Hi, anyway when i could help you maybe just a little bit, please give me some rating! thanks in advance. Nice regards
Kampi Posts: 366 Rating: (30)
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