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Step 5 MAB instruction

Created by: Ronaldo Junior at: 10/16/2014 8:26 PM (6 Replies)

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10/16/2014 8:26 PM	Rate (0)
Ronaldo Junior Experienced Member Joined: 2/22/2008 Last visit: 10/16/2024 Posts: 59 Rating: (6)	Dear all, I would like to know how to convert the S5code below. My doubts are about the MAB, LRW, SLD instructions. DECL: STAR EW (DW0) L DL 4 ADD DH 000EEC00 MAB LRW +0 SLD 4 MAB LW=STAR LKH 00FF UW T MW248 Hope someone helps!
	Best Regards Ronaldo Schittini Gardoni Junior Primetals Technologies ------------------------------------- Helpful? Rate it. Solved? Post it.
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10/18/2014 6:58 AM	Rate (1)
Navnag Platinum Expert Joined: 11/21/2007 Last visit: 9/25/2024 Posts: 2325 Rating: (308)	Hello Ronaldo Schittini Gardoni Jr This seems to be a program code based on indirect addressing. Here is a short description of the instructions that you are looking for : MAB - Transfer the contents of ACCU 1 ( Accumulator-1 ) to the base address register (20 bits) LRW - add the specified constant to content of the BR register and load the word addressed in this way in ACCU-1-L SLD - Shift a double word to the left (vacant positions to the right are padded with zeros) You can find more description of these instructions in S5-155U CPU 948 Programming Guide Unfortunately there are no easy methods of converting such code. You will need to understand the application and do a manual re-programming. Hope this helps Cheers Navnag
	There is no such thing as the last bug in a program There are no stubborn bugs, There are only stubborn Debuggers.
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10/20/2014 3:21 PM	Rate (0)
Ronaldo Junior Experienced Member Joined: 2/22/2008 Last visit: 10/16/2024 Posts: 59 Rating: (6)	Dear Navnag, Thank you for your answer. By the way, I have read this documentation and the instructions are clearer right now. Now the question for converting is about the Address Distribution. It is not very clear for me. Do you know what means the parameter DH 000EEC00? It should be a position in the Flag area. But I am not sure about it.
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10/20/2014 8:41 PM	Rate (1)
Navnag Platinum Expert Joined: 11/21/2007 Last visit: 9/25/2024 Posts: 2325 Rating: (308)	Ronaldo Junior Do you know what means the parameter DH 000EEC00? It should be a position in the Flag area. But I am not sure about it. Hello Ronaldo Junior You are thinking in the right direction. I would suggest that you go through Ch 9.4 Operations with the Base Address Register (BR Register) . It explains in details the use of Base Address Register . Some of the Important start addresses ( For CPU 948 ) are : 000E F800 H - Counters 000E FA00 H - Timers 000E FC00 H - Flag Area ( I would like to believe that 000E EC00 was an error ) 000E FE00 H - PII ( Process Input Image ) 000E FE80 H - PIQ ( Process Output Image ) Hope this helps Cheers Navnag
	Last edited by: Navnag at: 10/20/2014 8:43 PM There is no such thing as the last bug in a program There are no stubborn bugs, There are only stubborn Debuggers.
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10/20/2014 8:54 PM	Rate (0)
Ronaldo Junior Experienced Member Joined: 2/22/2008 Last visit: 10/16/2024 Posts: 59 Rating: (6)	Dear Navnag, This is what was missing for me. I found the data on page 330 of the referred manual. Thanks for helping me!
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11/3/2014 6:48 PM	Rate (0)
Ronaldo Junior Experienced Member Joined: 2/22/2008 Last visit: 10/16/2024 Posts: 59 Rating: (6)	Dear all, I have one doubt related to the LRD/TRD instructions. Unfortunatelly I have no chance to test it in the Office. Could anybody help me in the result? See the code below: L 45 //LOAD INTEGER VALUE 45 TO ACCU-1 ADDDH 000EEC00//ADDMEMORY POSITION OF THE ADDRESS LIST DB 0 MAB //TRANSFER ACCU1 TO THE BASE REGISTER LRW +0 //ADD THE CONSTANT (+0) TO THE BASE REGISTER AND LOAD THE ADDRESS OF THE WORD SPECIFIED INTO ACCU1-L SLD 4 //CONVERT ADDRESS TO PARAGRAPH ADDRESS MAB //TRANSFER ACCU1 TO THE BASE REGISTER TMD240 //TRANSFER ACCU1 TO MD240 L MD240//LOAD MD240 TO ACCU1 MAB//TRANSFER ACCU1 (MD240)TO BASE REGISTER LRD +30 //ADD THE CONSTANT (+30) TO THE BASE REGISTER AND LOAD THE ADDRESS OF THE WORD SPECIFIED INTO ACCU1 T MD236//TRANSFER ACCU1 TO MD236 L KG 10.0 //LOAD REAL VALUE 10.0 TO ACCU1 TRD+30//ADD THE CONSTANT (+30) TO THE BASE REGISTER AND TRANSFER THE CONTENTS OF ACCU1 (10.0) TO THE ADDRESS OF THE DOUBLE WORKD SPECIFIED. My question is the following: What is the content of the double word MD240? What is transferred to the double word MD236? Is it the value or the addressing? I am not sure about the content of both double words. When executing the instruction TRD30, where is the value 10.0 written? Hope I was clear in the explanation.
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11/12/2014 5:55 AM	Rate (2)
fritz Diamond Expert Joined: 10/7/2005 Last visit: 11/19/2024 Posts: 3027 Rating: (1057)	Hello Ronaldo Junior here's my take on your questions: Q1: What is the content of the double word MD240? A1: FD240 contains the absolute memory address of DW0 of DB45 Q2: What is transferred to the double word MD236? A2: FD236 contains the value from DD30 of DB45 (before DD30gets overwritten with a value of 10.0) Q3: When executing the instruction TRD30, where is the value 10.0 written? A3: It is written into DD30 of DB45 I hope this helps
	Cheers fritz The advice and opinion given in this thread is that of the author and does not necessarily reflect the views of I S Systems Pty Limited. To find out how I S Systems can help you with your automation needs please visit www.issystems.com.au.
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