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Moving an Actuator

Created by: bs_tz at: 2/8/2019 1:08 AM (18 Replies)

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2/13/2019 1:42 PM	Rate (1)
ixo65 Grandmaster-Expert Joined: 12/18/2014 Last visit: 11/3/2024 Posts: 34132 Rating: (4250)	I try the second version. I hope that it meets your wishes. Attachment Setpoint_0BA8.Standard_V2.zip (270 Downloads)

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This contribution was helpful to 1 thankful Users bs_tz

2/18/2019 1:29 PM	Rate (0)
bs_tz Member Joined: 2/10/2018 Last visit: 9/24/2024 Posts: 9 Rating: (0)	ixo65 I try the second version. I hope that it meets your wishes. Thank you for the time, that you have spend on this. I am impressed that you have taken the time to make this, to help me.

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2/18/2019 1:32 PM	Rate (0)
ixo65 Grandmaster-Expert Joined: 12/18/2014 Last visit: 11/3/2024 Posts: 34132 Rating: (4250)	b_s ixo65 I try the second version. I hope that it meets your wishes. Thank you for the time, that you have spend on this. I am impressed that you have taken the time to make this, to help me. Hello b_s, you're welcome. Is your problem then solved?

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2/18/2019 4:12 PM	Rate (0)
bs_tz Member Joined: 2/10/2018 Last visit: 9/24/2024 Posts: 9 Rating: (0)	almost But how do i change, so that the I6 only gives a signal to start the movement, and not retracted from length of the movement. Maybe i am doing it wrong? i have rewritten explanation. A counter counts the digital signal from (I6) to a given value (677) that indicates that the plane has made full rotation, The counter resets when the full rotation is reached, and starts the cycle again. The movement of the actuator is only started, when the a full rotation has happened. The distance that the actuator moves is controlled by 2 digital inputs (I1 - I2), where (I1) increases the distance and (I2) decreases the distance. (this works perfectly) But if no input is activated, then the movement distance remains the same. If input (I4) is high, then the actuator must return to start(Q2). (this works perfectly)

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2/18/2019 4:28 PM	Rate (0)
ixo65 Grandmaster-Expert Joined: 12/18/2014 Last visit: 11/3/2024 Posts: 34132 Rating: (4250)	I'm sorry, but I'm having trouble understanding your description because I do not understand the context of the signals. You know what you have and what it should do, I do not know the devices and therefore no idea about the function of the system.

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This contribution was helpful to 1 thankful Users NIBOU

2/18/2019 6:32 PM	Rate (0)
NIBOU Bronze Member Joined: 10/20/2015 Last visit: 7/13/2024 Posts: 94 Rating: (19)	Hello b_s I don't understand either what you want. The program that ixo has made for you working precisely as your description the previous days. Have you tested at the field and is not working as you want, or you tested only with the simulator?

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2/20/2019 10:33 AM	Rate (0)
bs_tz Member Joined: 2/10/2018 Last visit: 9/24/2024 Posts: 9 Rating: (0)	I understand that is problematic, if my explanation is not clear. I have made some alterations to your program, which is working in large parts. But i am having trouble getting the setpoint addition / retraction to work. B010 should get ether a setpoint addition or retraction from I1 or I2, This mathematical function is made every time the Rotation Complete Signal is sent from I6. Set_Aq+I1 or Set_Aq-I2 But if no setpoint addition or retraction is added via i1/i2, then the previous setpoint set_Aq should be added to the Aq in B011 when the rotation complete signal is sent. Set_Aq +Aq But i cant get it to accumulate the setpoint value in Aq Set_Aq starts out at 1 I6=Set_Aq +Aq setpoint = 1+1=2 I6=Set_Aq +Aq setpoint = 1+2=3 I6=(Set_Aq+ i1)+Aq setpoint = (1+0.5)+3=4.5 I6=(Set_Aq+i1)+Aq setpoint = (1.5+0.5)+4.5=6.5 I6=Set_Aq +Aq setpoint = 2+6.5=8.5 I6=Set_Aq +Aq setpoint = 2+8.5=10.5 I6=(Set_Aq-i2)+Aq setpoint = (2-0.5)+10.5=9 I6=(Set_Aq-i2)+Aq setpoint = (1.5-0.5)+9=10 I6=(Set_Aq-i2)+Aq setpoint = (1-0.5)+10=10.5 I6=Set_Aq+Aq setpoint = 0.5+10.5= 11 I6=Set_Aq+Aq setpoint = 0.5+11= 11.5 is this even possible? Attachment Setpoint_0BA8.Standard_V3.lsc.zip (241 Downloads)

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2/20/2019 11:02 AM	Rate (0)
ixo65 Grandmaster-Expert Joined: 12/18/2014 Last visit: 11/3/2024 Posts: 34132 Rating: (4250)	Now I can not understand anymore what you want to do. Attachment Untitled.PNG (277 Downloads)

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2/20/2019 12:31 PM	Rate (0)
bs_tz Member Joined: 2/10/2018 Last visit: 9/24/2024 Posts: 9 Rating: (0)	Set_Aq starts as value 1 I1 adds value to the Set_Aq I2 retracts value from the Set_Aq Aq accumulates the value from the calculation.

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