0_Einstein

Perhaps something I wrote a couple years ago may help:

https://support.industry.siemens.com/forum/WW/en/posts/pid-compact-plcsim/271803

FRANCK HERVE

Hello everyone,

I am writing this message to strongly request your help.

I am programming a compact PID to give a speed reference to its output and also to the analog output of the PLC to run a winding motor via a speed variator.

I have configured the compact PID and edited the program.

As you can see from the attached files, I send the speed reference by calculation (coil width, cable diameter, coil internal diameter, speed reference entered from a display) with a ramp function block.

I put the calculated speed at the "detpoint" input of the PID block.

And normally at the "Input" input of the PID block, I should put the speed feedback from the variator via an analog input of the PLC, i.e. IW0 at the "INPUT" input of the PID block.

but as I am simulating the program to see how it works, I use the same instruction after calculation divided by 1.005 so that there is a slight difference and I put it at the INPUT input of the PID.

but I notice that the PID does not give anything at its output or the PID does not work, I really need your help to solve this problem

my engine has a nominal speed of 1500 rpm coupled to a reducer with a ratio of 10:1, hence the speed of the coil on which the cable must be wound is 1500/10 = 150 rpm and this is the value that I use in the configuration of the pid block.

see attached file for details

 

so, I would like to know if the configuration of the compact pid block that I had to do is correct and that if I physically load into the s7-1200 cpu that I used during programming, the PID block will be able to work, I specify that I wrote the program with tia portal v19.

if I understood you correctly, the simulation with the s7-1200 cpu is not possible with the compact pid block but rather it is possible with the s7-1500 cpu