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mm430 and mm440 heat loss

Created by: Solution Riders at: 6/11/2010 9:25 AM (4 Replies)

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6/11/2010 9:25 AM	Rate (0)
Solution Riders Posts: 112 Rating: (0)	dear experts, i have working with mm430- 75 kw and mm440 -1.5 kw ac drive . MM430 75KW==6SE6430-2UD37-5FA0 MM430 1.5KW==6SE6440-2UD21-5AA1 i want know what is heat lossvalueof above mentioned the same?... kindly give us reply.
Solution Riders Posts: 112 Rating: (0)
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6/11/2010 2:54 PM	Rate (0)
JensS Posts: 739 Rating: (55)	please find the answer in FAQ: http://support.automation.siemens.com/WW/view/en/22978972
JensS Posts: 739 Rating: (55)
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6/11/2010 2:57 PM	Rate (0)
JensS Posts: 739 Rating: (55)	dearating tables please find in the mauals; for power losses please see FAQ: http://support.automation.siemens.com/WW/view/en/22978972
JensS Posts: 739 Rating: (55)
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6/11/2010 3:20 PM	Rate (0)
Solution Riders Posts: 112 Rating: (0)	dear jenss, thanks for reply,but you given bothFAQ link not open. Kindly give us reply. thanks in advance.
Solution Riders Posts: 112 Rating: (0)
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6/12/2010 12:11 AM	Rate (1)
Graeme Platinum Expert Joined: 6/4/2008 Last visit: 11/25/2025 Posts: 1521 Rating: (327)	Hi, here is the text and the attachment from JensS' link Cheers, Graeme Like all electrical equipment, inverter drives produce waste heat. This heat must be removed to prevent the drive overheating. As most commercial electronics is limited to 70°C (the internal junction temperature must be limited to 125°C or 150°C, but is usually maintained below this), the maximum temperature of the cooling air surrounding, or supplied to the drive is therefore limited to 50°C. For some types and applications, this is reduced further to 40°C (see operating instructions and specification for details). It is normal to install the drives, together with other equipment, in a cabinet or similar installation. The temperature of the air inside the cabinet must therefore be calculated. In some cases, cooling air may be supplied by an external fan or ducting. In these cases, the calculation will need to account for the amount of air, as well as its temperature. As part of the design of the installation, the following steps should allow the calculation of the temperature rise, and a suitable cooling system selected. 1. Determine the total power dissipated in the cabinet under worst case conditions (= ambient temperature in the cabinet). 2. Determine the maximum temperature of the air outside the cubicle, or the temperature of the air fed to the cubicle if ducted air is used. 3. Calculate the temperature rise. If this is too high, consider a different cooling solution (see PDF_additional_text). Details to calculate the temperature and power losses are in the attached file. Attachment PDF_power_loss_and_temperature_rise_en.pdf (328 Downloads)

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