Hello.

First let's look at your motor nameplate.

1. You have 17.2A arm current, that means you should select as min 6RA8018 with rated DC current 30A.

2. Look at field. Your rated motor current 1.35A. In selected 6RA8018 it is 5A, it is ok.

3. Then look at motor rated arm voltage, you have 500VDC. So you should look at 6RA8018-6FV62, which rated arm voltage is 500 VDC.

4. Then check your arm input supply voltage. If it is 460VDC, as on your old Simoreg nameplate, then 6RA6018-6FV62 with rated input voltage 480AC (+10%/-20%) is ok.

5. Check the overload capability of your motor. Usually it is 2*rated current. If it is higher then 2*rated current (e.g. your motor has 3*rated current overload capability, so its max current is 3*17.2=51.6A), then you should check if the converter could provide the required max arm current. Rated overload of 6RA80 is 1.8 of rated converter current. For 6RA8018 it is 30*1.8=54A. So even for 3*rated current overload of your motor it is sufficient. If you need higher current dew to overload capability, then you should select 6RA8025.

6. Check do you need 4Q-drive or 2Q-drive, Your suppliers suggest you 4Q-drives. I'm not sure which type is your old Simoreg 2Q or 4Q. If it is sufficient 2Q-drive then select 6RA8025-6FS22, as it is the min with 480AC supply voltage.

7. The last. OK. You could select the drive as your old Simoreg, It is 460VAC, 56A DC, 500VDC. In this case your new drive will be 6RA8025-6FS22 (2Q) or 6RA8025-6FV62 (4Q).