Hello,

I´ve calcualte the following:

90° in 25ms ==> Acceleration=288000°/s²
reached speed = a * t = 288000°/s² * 25ms = 7200°/s = 1200rpm
Motorinertia I´ve find: J = 0,0248kgm²

Required torque = J * ALPHA = 0,02148 * 2 * PI * 1200/60 / 25ms = 108Nm

This should be possible for the 1FT7108 (maybe use a little smoothing for the electrical time constant for the motor und make a good tuning).

Best regards

  Zako

zako_

Hello,

I´ve calcualte the following:

90° in 25ms ==> Acceleration=288000°/s²
reached speed = a * t = 288000°/s² * 25ms = 7200°/s = 1200rpm
Motorinertia I´ve find: J = 0,0248kgm²

Required torque = J * ALPHA = 0,02148 * 2 * PI * 1200/60 / 25ms = 108Nm

This should be possible for the 1FT7108 (maybe use a little smoothing for the electrical time constant for the motor und make a good tuning).

Best regards

  Zako

 thanks for your detailed answer, but where do you use in your calculations

Electrical time constant 27.50 ms (for this motor 27.50 ms) ?

zako_

Hello,

I´ve calcualte the following:

90° in 25ms ==> Acceleration=288000°/s²

 Of the Topic,

Hello Zako_,

Could you please expalin how you calculate acceleration value 288000⁰ /S² ? 

a = 2 * s /( t * t) = 2 * 90` / (25ms * 25ms) 

zako_

a = 2 * s /( t * t) = 2 * 90` / (25ms * 25ms) 

TechTeam

So without external intertia it would be possible.

 but how it can be calculated, formulas, technical data of the motor?

Hello

you know the required torque and so the required current now.

The inductivity is only 1,1mH and the DC link should be approx. 540V at 3AC 400V line supply.

Zako