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| 4/16/2013 2:07 PM | |
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Posts: 166 Rating:
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Dear Sir Thanks a lot for your reply Please refer to attached PLC Program. We would be retaining same program and add one network in FC10 as per your instructions to see how it works with Pause Button of Station 1, once we find it to be working alright, we will add 3 more Similar Networks using Pause Buttons for other stations Kindly confirm if it is correct to proceed this way' Best Regards, M. Rishikesh AttachmentVinarLine2.zip (235 Downloads) |
Last edited by: O_Moderator at: 4/16/2013 2:10 PM |
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| 4/26/2013 7:08 AM | |
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Posts: 166 Rating:
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Dear Sir Pl refer to my previous thread and also Step 7 Program attached Our requirement on Assembly Conveyor is as follows : When opearator presses Pause Button (having Input I2.1), conveyor should continue running for say 60 seconds and after that it should stop but within 60 seconds if operator presses same Pause Button again then conveyorshould continue running, with this , in case of minor problem , operaotor would be able to fix it say within 60 seconds and defect wont move to next station and in case he is unble to fix within 60 seconds, then conveyorwould stop As per earlier instructions, we would like to keep entire program intact and add network 15 in FC10 as per following A I2.1 FP M2.1 X Q1.1 (Q 1.1 = CONVEYOR RUN COMMAND) A ESTOP = M1.7 A M1.7 LS5T#60S SF T0 AN I2.1 R T0 A T0 = Q1.1 Kindly confirm if it is ok because when we had tried this once then we dont know why we found conveyorwas stopping as per logic with other push buttons(which have not been programmed)for pause but not with Push Button (I2.1) which has been programmed, v could not check further as we had to hand over Line for Production Best Regards, M. Rishikesh AttachmentVinarLine2.zip (234 Downloads) |
Last edited by: O_Moderator at: 4/26/2013 7:53 AM |
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| 4/28/2013 8:27 PM | |
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Posts: 197 Rating:
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Dear MRishikesh, This application looks interesting. I was actually trying to realize it in LAD (Ofcourse the STL solution may be effective and sufficient but I was, instead,exploring possibilities in LAD). As I understand, if you press that PB once in 1 min -> Conv should stop. if you press twice in 1 min -> Conv, should continue running. I was just wondering, how the conv. will start back again if it had come to stop by the 2nd case above. Is there any other I/P to restart? Besides, what will happen if some one will press the PB more than twice (i mean 1 min is enough time to press it more than 2 times). Again , the STL solution you worked upon may ward off these possibilities but I was just curious to know the likelihood of the situations that may come across.Plz bear with my questions but this looks like an interesting assignment, Regards |
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