4/11/2025 2:16 PM | |
Joined: 9/6/2023 Last visit: 8/27/2025 Posts: 6 Rating:
|
Hi, can you provide more info, maby pictures can help you |
5/3/2025 1:12 AM | |
Joined: 3/28/2010 Last visit: 9/12/2025 Posts: 1172 Rating:
|
AI card manual here: https://support.industry.siemens.com/cs/de/en/view/59753624 Rambling Rant ON Yet another 3-wire voltage device trying to connect to a Siemens analog input, but Siemens does not recognize the existence of 3-wire devices with a common connection between signal ground and DC power ground. Siemens calls a 4-wire transmitter one with 2 separate wires for DC (or AC) power and 2 separate wires for a signal output, and so does the rest of the world.. Siemens calls a 2-wire transmitter one that needs a DC power supply in the loop, so the transmitter only has 2 wires. That is also conventional terminology, But Voltage output devices are typically 3-wire or 4-wire, never 2-wire, like a 2-wire loop powered current output transmitter. So is a "2-wire voltage" device, assumed to have 2 separate power wires, but since there is no 2-wire, loop powered voltage instrument (what the rest of the world calls 4-wire voltage device) Siemens calls a 2-wire voltage device? How would anyone ever find out? You're just supposed to know. I have to speculate that such is the case. Rambling rant OFF. I would have wired it the same way you have wired it. What voltage is the UV0 terminal providing? with respect to UV- or M, if available. Can you apply a pressure to get the output off zero and measure to see if the signal output, with respect to M(0) goes to some voltage value (with a voltmeter on the U and M terminals), meaning that instrument is getting DC power and operating, but the signal is not being recognized by the AI card. If the transmitter changes output with pressure, then my suggestion is to try momentarily jumpering M (Analog ground) to UV0 to see if that produces the grounding needed for the signal to be 'seen' by the AI card. That's assuming the M terminal is somewhere on the terminal block, which it might not be. It might only be on the "light BaseUnit". But the diagram shows M is isolated from the voltage input A/D, so even that might not work.
|
Last edited by: Moderator_Lan at: 05/05/2025 06:48:54link optimized |
|
Follow us on