9/6/2021 9:44 PM | |
Joined: 9/27/2006 Last visit: 4/27/2024 Posts: 12257 Rating: (2665) |
Hello gzzy; Are you quite sure that this is the modue you need? It is described as a digital input module, 8 x 24VDC, not an analog input module. https://support.industry.siemens.com/cs/ww/en/view/59753552/101165497099 You cannot read 4-20 mA analog signals with such a module. Hope this helps, Daniel Chartier |
Last edited by: dchartier at: 09/06/2021 21:45:54 |
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9/6/2021 11:10 PM | |
Joined: 9/27/2006 Last visit: 4/27/2024 Posts: 12257 Rating: (2665) |
Hello gzzv; That part number corresponds to an analog inputt module, 4 x 4-20mA, so you can use it with your Lenze drive current outputs. The manual for your module shows how to wire the unit: https://support.industry.siemens.com/cs/ww/en/view/59768161/115287918859 Note: this tyoe of documnt is very easy to locate, if you have the pt number, or the description. Simply use the search box at the right of this page, with 6ES7134-6GD01-0BA1 as a search term, and filter by "Manuals" in the Search Area selection box. Try it.. Now, you describe the analog outputs as "active": You stated earlier "The Frequency Drive has an internal supply to send out 4-20mA according the motor current and frequency".. In analog witring terms, this is a 4-wire transducer, using 2 wires for the signal and 2 wires for the module power. When the analod input module is asked to power the transmitter, we call this a current loop or 2-wire transducer See this article for a few more explanations: https://www.predig.com/indicatorpage/back-basics-loop-vs-line-power So connect your 2 analog oututs from the drive as 4-wire connections on 2 separate channels of the analog input module you are using. Hope this helps, Daniel Chartier |
Last edited by: dchartier at: 09/06/2021 23:12:42 |
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