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Because the bit is not reset?

Created by: automatizzando at: 1/11/2012 10:34 PM (3 Replies)

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1/11/2012 10:34 PM	Rate (0)
automatizzando Bronze Member Joined: 3/11/2007 Last visit: 12/5/2022 Posts: 220 Rating: (12)	EXAMPLES In the two attachments I have a bit (M10.5) that when activated with the instruction set, the reset instruction is not executed. I do not understand why. What's wrong? Attachment Set-Reset.pdf (107 Downloads)

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1/11/2012 10:54 PM	Rate (0)
0_Einstein Diamond Expert Joined: 7/7/2010 Last visit: 2/6/2023 Posts: 13081 Rating: (2124)	If you look at the comparators on the left and right, they are mutually exclusive, so the RESET never happens. [code] If (A > B) then do some math if result of math is within range then move some data if (A <= B) then reset some bits end-if end-if First time this happens, set a bit end-if [/code] Look at the (A > B) and (A <= B). Not possible.
	science guy
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1/11/2012 11:17 PM	Rate (0)
automatizzando Bronze Member Joined: 3/11/2007 Last visit: 12/5/2022 Posts: 220 Rating: (12)	Ok. I understand what you mean. But because M10.7 (Reset OK) Look at the (A > B) and (A <= B). Not possible. Do not apply the same rule for M10.5 and M10.7? M10.7 reset OK M10.5 No reset
	Last edited by: automatizzando at: 1/11/2012 11:21 PM Last edited by: automatizzando at: 1/11/2012 11:20 PM Last edited by: automatizzando at: 1/11/2012 11:19 PM
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1/11/2012 11:29 PM	Rate (0)
0_Einstein Diamond Expert Joined: 7/7/2010 Last visit: 2/6/2023 Posts: 13081 Rating: (2124)	When A > B, it cannot ALSO be true that A<=B. Your rung of logic has them in series, meaning AND, so in essence, you are saying this: If (A > B) AND (A <= B) THEN (RESET BIT) If (A > B) THEN (FIRST TIME ONLY, SET BIT) The reset bit portion can never happen.
	science guy
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