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12/4/2014 7:55 PM | |
Posts: 5225 Rating: (1185) |
Hi. Try this [LINK]. Use the formulas.. V = I x R.....EQ1 P = V x I ....EQ2 Then combining EQ1 and EQ2 to get the formula: P = (I x R) x I = I2 x R.... EQ3 Now let us assume you get standard 0.25W resistor.. 0.25 = (0.020)2 x R >>> R = 625ohm So.. if you select a resistor smaller than 625ohm you will not burn out the resistor. Now using EQ1 we can calculate that V = 12.5V. We need to keep in mind that the voltage will have a ceiling.. 10V - which is less than 12.5V. In EQ1 it calculates as R = 500ohm. Finally... R = 320ohm, 0.25W will work for you to measure 0 to 6.4V. Does this work for you? w |
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