date and time of day format

Yes, I had created C functions for that:



char* IECDate_Extract(unsigned short IECDate, char* Format)
{
struct tm *ptr;
time_t CTime;
char* Display = SysMalloc(49);
long IEC2CTime = 631152000; // seconds between "01/01/1970 00:00:00" and "01/01/1990 00:00:00"
long Fuso = 10800; // seconds to ajust your time zone (e.g. 60x60x3)
long DaySeconds = 86400; // seconds in one day (60x60x24)

if(IECDate <= (2147483647 - (IEC2CTime + Fuso)) / DaySeconds)
{
// convert the number of days after "01/01/1990" to the number of seconds after "01/01/1970 00:00:00"
CTime = (IECDate * DaySeconds) + (IEC2CTime + Fuso);
ptr = localtime(&CTime);
strftime(Display, 25, Format, ptr);
return Display;
}
return "overflow";
}



char* TimeOfDay_Extract(unsigned long TOD, char* Format)
{
struct tm *ptr;
time_t CTime;
char* Display = SysMalloc(49);
long Fuso = 10800; // seconds to ajust your time zone (e.g. 60x60x3)
long DaySeconds = 86400; // seconds in one day (60x60x24)

if(TOD < (DaySeconds * 1000))
{
// convert the miliseconds after "00:00:00:000" to seconds after "01/01/1970 00:00:00"
CTime = (TOD / 1000) + Fuso;
ptr = localtime(&CTime);
strftime(Display, 25, Format, ptr);
return Display;
}
return "overflow";
}


Obs1: The "Format" parameter must be something like "%d %m %y"

Obs2: Some may think that the use of C time functions on the "TimeOfDay_Extract"could be simplifiedto math operators. Butit's use forcode robustness.

See ya,
Dimitri.

tmm

Hello Dimi,

please excuse my latereply to your help.
I solved the problem by using VBScript, but your code will be usefull for me infuture projects.

Thanks a lot