Hello.

I have
SINAMICS PM240-2
SINAMICS CU250S-2 USS
Motor FUKUTA ST90MB (looks like SF 2.2kW 2000RPM) ([snip])
Encoder HES-1024-MHT (connected with X136 terminal)

When I run motor identification, I get an error: 7982 : Drive: Rotating measurement encoder test(7)

p0408=1024

The values of r479 r482 (actual position) per one revolution are 2 ^ 21 (1024 * 2048). It is not clear to me why not 1024. Counting working right?

I understand that I receive the wrong number of pulses from the encoder. I can not find an error. What could be the problem?

Thank you.

P.S. I read https://support.industry.siemens.com/tf/WW/en/posts/drive-commissioning-error/20537?page=0&pageSize=10 

In the configuration, temporarily change the control / feedback strategy from <whatever> + encoder to <whatever> + encoderless.

Commission as much as you can without the encoder for feedback.

The encoder A/B direction could be reversed.  You can adjust it in drive configuration using Drive Navigater -> Encoder and invert the encoder signal.

Or, you can swap A/-A & B/-B (and Z/-Z).

Turn the shaft one revolution, or as close as you can to one revolution.  Monitor the encoder raw input and calculate the difference in pulses.  If you have approximately the correct PPR for the encoder configuration (quadrature or single channel for example), the wiring and encoder are ok.

If there is something wrong with the count or it seems to count strangely, verify the wiring, maybe even using an o-scope.

AlxndrBo

Hello.

I have
SINAMICS PM240-2
SINAMICS CU250S-2 USS
Motor FUKUTA ST90MB (looks like SF 2.2kW 2000RPM) ([snip] )
Encoder HES-1024-MHT (connected with X136 terminal)

When I run motor identification, I get an error: 7982 : Drive: Rotating measurement encoder test(7)

p0408=1024

The values of r479 r482 (actual position) per one revolution are 2 ^ 21 (1024 * 2048). It is not clear to me why not 1024. Counting working right?

I understand that I receive the wrong number of pulses from the encoder. I can not find an error. What could be the problem?

[snip] 

Thank you.

P.S. I read https://support.industry.siemens.com/tf/WW/en/posts/drive-commissioning-error/20537?page=0&pageSize=10 

... to the formula 1024 * 2048.

Check p418. The standardsetting fits to a SIN/COS encoder (2^11 fine- resolution).

If you like, you can write "2" there - then you get a factor of 2^2 = 4 times your HTL tracks (1024=

==> r479 would be changed by 4096 per rev then.

huggy_d1

In the configuration, temporarily change the control / feedback strategy from <whatever> + encoder to <whatever> + encoderless.

Commission as much as you can without the encoder for feedback.

The encoder A/B direction could be reversed.  You can adjust it in drive configuration using Drive Navigater -> Encoder and invert the encoder signal.

Or, you can swap A/-A & B/-B (and Z/-Z).

Turn the shaft one revolution, or as close as you can to one revolution.  Monitor the encoder raw input and calculate the difference in pulses.  If you have approximately the correct PPR for the encoder configuration (quadrature or single channel for example), the wiring and encoder are ok.

If there is something wrong with the count or it seems to count strangely, verify the wiring, maybe even using an o-scope.

zako

... to the formula 1024 * 2048.

Check p418. The standardsetting fits to a SIN/COS encoder (2^11 fine- resolution).

If you like, you can write "2" there - then you get a factor of 2^2 = 4 times your HTL tracks (1024=

==> r479 would be changed by 4096 per rev then.

1. I use a unipolar encoder connection. -A, -B, -Z connected to GND.

2. When I direction reverse with p410[0].0, p410[0].1 or change wiring A and B contacts then I have 7982 : Drive: Rotating measurement encoder test(6)

3. Check encoder pulses: p408=1024, p418=2, rotate the shaft 20 turns => r479=81902 (1024 * 2^2 * 20 = 81920). I think the encoder is working properly.

4. Check encoder signal with measure speed: p1300=20, start motor, compare r21 vs r61. Setpoint 1800rpm, r21~1800, r61~900 OMG! Then I set p408=512 => closed loop speed control with encoder is work. Commissioning OK.

I am convinced that the encoder has 1024 ppr. Why does this work?

Now I set up torque control (p1300=23) and go to drink lemonade. But, if problems arise, I am counting on your help))

 I think it might come in handy.

Datasheet Website with datasheet page 300

Checking the encoder signal

If you use an encoder to measure the speed, you should check the encoder signal before the encoder feedback is active.

Procedure

1. Set the control mode "encoderless vector control": p1300 = 20.

2. Switch-on the motor with an average speed.

3. Compare parameters r0061 (speed encoder signal in rpm) and r0021 (calculated speed in rpm) regarding the sign and absolute value.

4. If the signs do not match, invert the speed encoder signal: Set p0410 = 1.

5. If the absolute values of the two values do not match, check the setting of p0408 and the encoder wiring.

You have ensured that the scaling and polarity of the encoder signal are correct