Elegant way of combining two specific BYTEs two an INT in SCL?

The Takstein

Hi all!

Been picking my brains of some elegant way of combining two BYTEs to an INT, anybody got an idea?

I have two BYTES ( a low byte and high byte) that i receive from the DP bus. These I want to combine in SCL. BYTE_TO_INT would only work for one of the bytes.

I'm sure i can work around it but it would be a bit messy.

Hope anybody has any ideas about this!

regards,
Takstein

VAR_OUTPUT
"WordOut" : Word;
"b_s" AT "WordOut" : Struct
"hiByte" : Byte;
"loByte" : Byte;
END_STRUCT;
END_VAR

BEGIN
#b_s.hiByte := #hiByte;
#b_s.loByte := #loByte;

END_FUNCTION_BLOCK

That said, the much easier way is to simply assign the bytes to the integer tag directly.

Let's say byte 1 => b0, and byte 2 => b1 (hi and lo bytes respectively), and your integer is int1.

int1.b0 := b0;
int1.b1 := b1;

Now int1's bytes are assigned the values. This can be done in ladder with two MOVE instructions.