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Created by: how come at: 3/13/2009 4:40 AM (6 Replies)

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3/13/2009 4:40 AM	Rate (0)
how come Posts: 382 Rating: (47)	Hi, Does anyone can help me to explain in details what this logic do? Thanks in advance. LAR1 P##SEND L B#16#10 T LB [AR1,P#0.0] L B#16#2 T LB [AR1,P#1.0] L 40 T LW [AR1,P#2.0] L #DATABLOCK T LW [AR1,P#4.0] L P#DBX 0.0 T LD [AR1,P#6.0] with regards, how come?
how come Posts: 382 Rating: (47)
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3/13/2009 5:34 AM	Rate (2)
fritz Diamond Expert Joined: 10/7/2005 Last visit: 5/30/2023 Posts: 2966 Rating: (1025)	Dear How come put simple, the logic isconstructing an ANY pointer (which ispresumably declared as type ANY in the TEMP area of the FC/FB and then used for a call to "SEND" function which uses the ANY pointer information to determine what data to send). ANY Pointer are 10 Bytes long and contain all the required information about adata area (e.g. start address, memory area (DB, I, Q, M etc.) what type of data (BYTE, WORD, REAL etc.) and how many of them etc.). Search the S7 inbuilt help for "ANY" and have a look at the format of the ANY pointer to find out more. While ANY pointers and usage of them generallybelongs into the "advanced" S7 programming category (and is not all that easily explained in a short post)I nonetheless added some hopefully useful explanations behind your logic: LAR1 P##SEND // Point AR1 to the start address of #SEND variable L B#16#10 T LB [AR1,P#0.0] // Write 10hex into byte 0 of the SEND ANYpointer L B#16#2 T LB [AR1,P#1.0] // Write2 into byte1 of the SEND ANYpointer (=nominate the DATA TYPE asBYTE) L 40 T LW [AR1,P#2.0]// Write 40 into byte 2 of the SEND ANY pointer (= nonimate the REPETITION FACTOR as40 (40 Bytes in this case since theDATA TYPE is declared as BYTE) L #DATABLOCK // I presume this variable has an INT number in it T LW [AR1,P#4.0]// Write the DB numberintoBytes4&5 of the SEND ANY pointer L P#DBX 0.0 T LD [AR1,P#6.0] // Write the memory area (DB) and start address(DBX0.0) intoBytes6->9 of the SEND ANY pointer I hope this helps at least a little bit Cheers Fritz
	Cheers fritz The advice and opinion given in this thread is that of the author and does not necessarily reflect the views of I S Systems Pty Limited. To find out how I S Systems can help you with your automation needs please visit www.issystems.com.au.
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3/13/2009 5:45 AM

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Eastern

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STEP 7 stores the parameter type ANY in 10 bytes. When constructing a parameter of the type ANY, you must ensure that all 10 bytes are occupied because the called block evaluates the whole contents of the parameter. If, for example, you specify a DB number in byte 4, you must also explicitly specify the memory area in byte 6.

STEP 7 manages the data of elementary and complex data types differently from the data for parameter types.

ANY Format for Data Types

For elementary and complex data types STEP 7 stores the following data:

Data types
Repetition factor
DB number
Memory area in which the information is stored
Start address of the data

image/1_a30typ_22_b_vec.gif

The repetition factor identifies a quantity of the indicated data type to be transferred by the parameter type ANY. This means you can specify a data area and also use arrays and structures in conjunction with the parameter type ANY. STEP 7 identifies arrays and structures as a number (with the help of the repetition factor) of data types. If, for example, 10 words are to be transferred, the value 10 must be entered for the repetition factor and the value 04 must be entered for the data type.

The address is stored in the format Byte.Bit where the byte address is stored in bits 0 to 2 of byte 7, in bits 0 to 7 of byte 8, and in bits 3 to 7 of byte 9. The bit address is stored in bits 0 to 2 of byte 9.

With a null pointer of the type NIL all bytes from byte 1 are assigned 0.

The following tables show the coding of the data types or of the memory areas for the parameter type ANY.

	Coding of the Data Types
Hexadecimal Code	Data Type	Description
b#16#00	NIL	Null pointer
b#16#01	BOOL	Bits
b#16#02	BYTE	Bytes (8 bits)
b#16#03	CHAR	Characters (8 bits)
b#16#04	WORD	Words (16 bits)
b#16#05	INT	Integers (16 bits)
B#16#06	DWORD	Words (32 bits)
b#16#07	DINT	Double integers (32 bits)
b#16#08	REAL	Floating-point numbers (32 bits)
b#16#09	DATE	Date
b#16#0A	TIME_OF_DAY (TOD)	Time of day
b#16#0B	TIME	Time
b#16#0C	S5TIME	Data type S5TIME
b#16#0E	DATE_AND_TIME (DT)	Date and time (64 bits)
b#16#13	STRING	String

	Coding of the Memory Areas
Hexadecimal Code	Area	Description
b#16#80	P	I/O area
b#16#81	I	Input area
b#16#82	Q	Output area
b#16#83	M	Bit memory area
b#16#84	DB	Data block
b#16#85	DI	Instance data block
b#16#86	L	Local data (L stack)
b#16#87	V	Previous local data

ANY Format for Parameter Types

For parameter types STEP 7 stores the data type and the address of the parameters. The repetition factor is always 1. Bytes 4, 5, and 7 are always 0. Bytes 8 and 9 indicate the number of the timer, counter, or block.

image/1_a30typ_23_b_vec.gif

The following table shows the coding of the data types for the parameter type ANY for parameter types.

Hexadecimal Code	Data Type	Description
b#16#17	BLOCK_FB	FB number
b#16#18	BLOCK_FC	FC number
b#16#19	BLOCK_DB	DB number
b#16#1A	BLOCK_SDB	SDB number
b#16#1C	COUNTER	Counter number
b#16#1D	TIMER	Timer number

LAR1 P##SEND Load the start address of the ANY pointer in AR1.

L B#16#10 Load the syntax ID and
T LB [AR1,P#0.0] transfer it to the ANY pointer.

L B#16#2 Load data type Byte and
T LB [AR1,P#1.0] transfer it to the ANY pointer.

L 40 Load 40 bytes and
T LW [AR1,P#2.0] transfer them to the ANY pointer.

L #DATABLOCK Source is DB(DATABLOCK)
T LW [AR1,P#4.0]

L P#DBX 0.0
T LD [AR1,P#6.0]

SO THE RESULT IS

P#DB(DATABLOCK).DBX0.0 BYTE 40.

REFER THIS EXAMPLE ALSO THIS WILL HELP U

FUNCTION FC10: VOID

VAR_TEMP

Source: ANY;

Target: ANY;

END_VAR

BEGIN

LAR1P#Source;

L B#16#10;
T LB[AR1,P#0.0];

L B#16#02;
T LB[AR1,P#1.0];

L 10;
T LW[AR1,P#2.0];

L 22;
T LW[AR1,P#4.0];
L P#DBX11.0;
T LD[AR1,P#6.0];

LAR1P#Target;

L B#16#10;
T LB[AR1,P#0.0];

L B#16#02;
T LB[AR1,P#1.0];

L 10;
T LW[AR1,P#2.0];

L 33;
T LW[AR1,P#4.0];
L P#DBX202.0;
T LD[AR1,P#6.0];

CALL SFC 20 (
SRCBLK := Source,
RET_VAL := MW 12,
DSTBLK := Target
);

END_FUNCTION

Load the start address of the ANY pointer in AR1.

Load the syntax ID and
transfer it to the ANY pointer.

Load data type Byte and

transfer it to the ANY pointer.

Load 10 bytes and
transfer them to the ANY pointer.

Source is DB22, DBB11

Load the start address of the ANY pointer in AR1.

Load the syntax ID and
transfer it to the ANY pointer.

Load data type Byte and

transfer it to the ANY pointer.

Load 10 bytes and
transfer them to the ANY pointer.

Target is DB33, DBB202

Call the system function BLKMOV

Evaluate the BR bit and MW12

REGARDS

3/13/2009 6:58 AM	Rate (0)
how come Posts: 382 Rating: (47)	Dear fritz and viveks, Thank you very much for the explaination. I am really appreciate the time you spend trying to explain the logic.. There is one portion which i don't quite understand. What is the syntax ID for? Is it always must be 10 bytes? L 10; T LB[AR1,P#0.0] load the syntax ID and transfer it to the ANY pointer with regards, how come?
how come Posts: 382 Rating: (47)
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3/13/2009 7:27 AM	Rate (0)
fritz Diamond Expert Joined: 10/7/2005 Last visit: 5/30/2023 Posts: 2966 Rating: (1025)	you aremost welcome how come? it is also a very good question indeed and the answer why the first byte of an ANY pointer must always have the valueof 10hex (for S7) is probably only known to Siemens themselves. Having said that, I'd like to stand corrected here, if anybodyelse knows the reasons for the 10hex please let us all know. Cheers fritz
	Cheers fritz The advice and opinion given in this thread is that of the author and does not necessarily reflect the views of I S Systems Pty Limited. To find out how I S Systems can help you with your automation needs please visit www.issystems.com.au.
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3/13/2009 7:34 AM	Rate (0)
Eastern Posts: 557 Rating: (64)	hi thank you very much for appreciate. yes it isa standard of siemens. in above figure in BYTE 0 IS 10h for S7. IT is a standard of siemens. for example pointer data type concept isglobally same, but representation is different in various system.
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3/13/2009 8:48 AM	Rate (1)
how come Posts: 382 Rating: (47)	O! i see. Thank youboth of you for clearing my doubt. and have a nice weekends! with regards, how come?
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