Hello All!

I need to archive tags and messages in HMI project. I have only 3 analog measurements and 100 messages. My client want to archive it for 90 days. I have SIMATIC HMI Memory Card 2GB. Is it enough ? Or may be I need more memory? 4, 8 GB?

WinCC Advanced V13 SP1 Up 4

Hello sjm_go,

if you click on your data log and then look to ist properties it tells you under "General > Data records per log" the maximum size of your log (the value is depending on how you configured the log, of course). Just add them and you shoud have a good estimate.)

If you need info about calculation the logging time or cycle time, see: https://support.industry.siemens.com/tf/ww/en/posts/129544/

Yes, It is correct - I create vizu at Comfort Panel. This is SIMATIC HMI TP1200 COMFORT  6AV2124-0MC01-0AX0. On Data Sheet I found: Number of archives per device 50; Number of entries per archive 20 000. So, I can archive 1 milion records, can't I? Is it possible? it is 7,7sec per one measure point, so it is too litle :/

Hello sjm_go,

it might work, but it's not guaranteed:

WinCC Advanced V13.0 SP1 - https://support.industry.siemens.com/cs/ww/en/view/109091876/56146218635

The specified maximum values are not additive. It cannot be guaranteed that configurations running on the devices at the full system limits will be functional.

Also, the "number of entries per log" is 20k with a TP1200.

If you want to have less time between the measurement points you can use long time archiving.

• "Long-Term Data Archiving with WinCC Runtime PC and SIMATIC HMI Operator Panels with WinCC (TIA Portal)"
  https://support.industry.siemens.com/cs/ww/en/view/109477071
  

This means you have a log < 90 days, but you use several logs, which in sum are at least 90 days long.

Example:

90d = 60s*60*24*90 = 7.776.000s

7.776.000s / 20.0000 = 388,8 s = 6,48 minutes --> This is too long.

a)
7.776.000s / 60s = 129.600

129.600 / 20.000 = 6,48 --> Number of logs you would need per tag, if you want to log the tag every minute. --> 7 logs

Each log is around 12-13 days long.

b)
7.776.000s / 7,7s= 1.009.870,13

1.009.870,13 / 20.000 = 50,5 --> Number of logs you would need per tag, if you want to log the tag every 7,7s. --> 51 logs

Each log is around 1,78 days long.

c)
7.776.000s / 8,64s = 900.000

900.000 / 20.000 = 45 --> Number of logs you would need per tag, if you want to log the tag every 8,64. --> 45 logs

Each log is 2 days long.

You might need to save the logs on a network location, as I don't know how much memory this will take, but it feels like a bit.

In case c) that would be around 4884KB/log * 45 = 219,78 MB for each tag over 90 days.

219,78 MB/ tag * 100 tags = 21,978 GB  --> so no SD Cards or USB stick in this case (and no mobile HDD either) --> save at Network path

or:
4884KB/log * 100 = 488,4MB * 4 days  --> copy the logs to another destination from the SD card at least every 4 days and clean the SD Card. (2 logs/tag) ore use the 8GB USB stick and empty it every 16 days (8 logs/tag).