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| 7/20/2013 6:08 PM | |
Joined: 11/21/2007 Last visit: 3/15/2023 Posts: 2321 Rating:
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Hi Sh4ne Please post the exact circuit diagram of the wiring done by you Thanks Navnag |
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There is no such thing as the last bug in a program |
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| 7/22/2013 2:55 PM | |
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Posts: 113 Rating:
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Attached are two versions of a voltage divider circuit. The first uses your 1.2K resistor in series with a potentiometer, the choice of 1.2K causes two problems, first you need a non standard potentiometer to get the voltage divider to give 0-10V. Second your resistors will be dissipating 0.28watts in total so you will need higher watt rated resistors. The second drawing shows the circuit with a more normal 5K pot and a 7K resistor to match. It could equally be a 10K pot with a 14K resistor. AttachmentVoltage divider.pdf (576 Downloads) |
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| 7/22/2013 3:05 PM | |
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Joined: 11/21/2007 Last visit: 3/15/2023 Posts: 2321 Rating:
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Hi Sh4ne As correctly suggested by "BryanG2001" , you need to use a voltage Divider circuit or if you have a 10V power supply available, you can use it directly across the Potentiometer. This is because the Analog inputs of CPU 1214C are only suitable for 0-10V Voltage signals and cannot directly measure the Potentiometer resistance. You need to have this circuit so that you can provide 0-10V to the Analog input. Good Luck Navnag |
Last edited by: Navnag at: 7/22/2013 3:05 PMThere is no such thing as the last bug in a program |
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