help to understanding the jump instruction

Hi Everyone

Could anyone of you help me understanding the jump instruction JBI.

It is believed to be working when BR=1

I am going to write my code here---

L 2

L 64

*I

JBI OVER

A I 1.6

A I 1.7

=Q 5.0

OVER:A I 2.1

A I 2.2

=Q 5.1

as I understand that programme should not run which is mentioned between jump instruction if  the BR is one rather it should jump to level over.

I multiplied two values 64 and 2 which gives us 128 decimal and equivlant binary 10000000. it means 8TH BIT br is 1 but it still does not jump to the level OVER and keep scanning all the  program in sequence.

any idea why<?

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Split from help me to understand STL instructions.

Manmohan Sharma

Hi Everyone

Could anyone of you help me understanding the jump instruction JBI.

It is believed to be working when BR=1

I am going to write my code here---

L 2

L 64

*I

JBI OVER

A I 1.6

A I 1.7

=Q 5.0

OVER:A I 2.1

A I 2.2

=Q 5.1

as I understand that programme should not run which is mentioned between jump instruction if  the BR is one rather it should jump to level over.

I multiplied two values 64 and 2 which gives us 128 decimal and equivlant binary 10000000. it means 8TH BIT br is 1 but it still does not jump to the level OVER and keep scanning all the  program in sequence.

any idea why<?

Hello Manmohan Sharma,

you posted the same question in another thread. You can find it here: Help me understand the jump instruction JBI

Thank you
The Helping Hand