6/17/2008 11:39 AM  
Joined: 3/26/2008 Last visit: 12/23/2020 Posts: 51 Rating: (0) 
My greetings to everybody. 
6/17/2008 12:02 PM  
Posts: 34 Rating: (0) 
This comes from the physical definition of the axis. When you define how many revs of the physical (i.e. motor) axis result in how many revs of the output shaft (i.e. is there a gearbox) and then how many revs of the output shaft translates into distance of the external axis. Please note as well that when you 'Add an axis' there is a selection for your rotary or linear and if the values that go with each of these selections (mm/s or rads/sec or degrees/min etc) Cheers Stuart 
6/17/2008 12:21 PM  
Posts: 33 Rating: (4) 
Dear Andrew_097 Here is your answer: v= (2*pi*n*r*1000)/60 [mm/s] where v  linear velocity pi  3,14 n  RPM r  radius  distance from axis of rotation on wich you want to count linear velocity Hope that is what you were looking for. Regards Jacekpro 
Last edited by: jacekpro at: 6/17/2008 12:21 PM 

6/17/2008 12:58 PM  
Joined: 3/26/2008 Last visit: 12/23/2020 Posts: 51 Rating: (0) 
Thanks for the answers, at last examined this question 
6/19/2008 8:25 AM  
Joined: 1/22/2008 Last visit: 6/29/2021 Posts: 39 Rating: (3) 
Its consider in witch unit is r, but if unit of radius r is [mm] then in my opinion: V = (n/60) * (2*pi*r) [mm/s] where: n  rpm  revolutions per minute r  radius [mm] Regards, SzymekEl 
6/19/2008 12:17 PM  
Joined: 3/26/2008 Last visit: 12/23/2020 Posts: 51 Rating: (0) 
The formula is correct, but i think that ruduction coefficient should be also taken into account. At last the formula should be like this (encoder mounted on motor side, motor revs/enc revs = 1) v = (n * pi * d) / (60 * i) = (n * Dist. per spindle rev.) / (60 * Number of motor revs / Num of load revs) where: n  drive speed [RPM] d  diameter[mm] 
7/2/2010 2:26 PM  
Posts: 7 Rating: (0) 
Dear Andrew, We can directly read RPM from axis "ActorData". Pl see in attachment. AttachmentSnap.zip (266 Downloads) 
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