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STL Pointer Write Offset

Created by: Multijack at: 10/19/2006 9:13 PM (3 Replies)

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10/19/2006 9:13 PM	Rate (0)
Multijack Posts: 3 Rating: (0)	Hi, Can someone explain why the code below sets the lowest bit in the SECOND word of Datablock 20 and not the lowest bit of the FIRST word? OPN DB 20 L P#0.0 LAR1 L 1 T DBD[AR1,P#0.0] Thanks.
Multijack Posts: 3 Rating: (0)
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10/20/2006 2:48 PM	Rate (0)
Cicero Gold Member Joined: 10/10/2005 Last visit: 3/1/2021 Posts: 1570 Rating: (101)	Hello, regarding to your inquiry we would like to inform you. But we can not reproduce your described question or problem. Please see our attached example program with your program code in FC1and the DB20 we have declared with the variable of type of ARRAY [1..20] OF DWORD. If we load the complete program code (FC1 is called in OB1) in the CPU, the lowest bit will be set in DBD0 (Address 0.0, Variable [1]). With best regards Cicero Attachment Ptest2.zip (56 Downloads)

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10/20/2006 3:58 PM	Rate (0)
Ates Bronze Member Joined: 8/22/2006 Last visit: 1/11/2021 Posts: 198 Rating: (16)	you are writing 1 not L#1 so it will write 00000000 00000000 0000000 00000001 so dbx dbb20 = 0 dbb21 = 0 dbb22 = 0 dbb23=1 whats wrong with it ? you are asking without knowing l 1 is integer but when you write double you need l#1 or there normally s7 writes dbs not ascending but decsending so you want to point this error. i think second one is sensless.. so you are in category 1 :)

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10/20/2006 4:37 PM	Rate (0)
Multijack Posts: 3 Rating: (0)	I see my problem. I had my Datablock defined as five words but I was using DBD which, I now realize, implies a Double Word. Thank-you for your help.
Multijack Posts: 3 Rating: (0)
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