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How to convert DWORD/DINT data to bytes in SCL

Created by: Ramenmaestro at: 6/24/2022 9:32 AM (4 Replies)

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6/24/2022 9:32 AM	Rate (0)
Ramenmaestro Member Joined: 2/21/2022 Last visit: 8/18/2025 Posts: 8 Rating: (0)	I need to convert a Dword or Dint data to 4 or more Bytes, such as mybyte.[0]=mydword(part1) mybyte.[1]=mydword(part2) mybyte.[2]=mydword(part3) mybyte.[3]=mydword(part4) How can i do it in SCL?Thanks a lot for any suggestion.

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6/24/2022 10:42 AM	Rate (0)
BoletusEdulis Silver Member Joined: 6/10/2015 Last visit: 9/5/2025 Posts: 474 Rating: (101)	Hi, if you can use sliced access, you can easily do mybyte.[0]=mydword.%B0 Ramenmaestro I need to convert a Dword or Dint data to 4 or more Bytes, such as mybyte.[0]=mydword(part1) mybyte.[1]=mydword(part2) mybyte.[2]=mydword(part3) mybyte.[3]=mydword(part4) How can i do it in SCL?Thanks a lot for any suggestion.
	Last edited by: BoletusEdulis at: 06/24/2022 10:43:06 B. Edulis --- If you have a doubt, there is no doubt
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6/24/2022 10:46 AM	Rate (0)
jacek d Platinum Expert Joined: 9/23/2005 Last visit: 9/8/2025 Posts: 5112 Rating: (768)	Here you can find some concepts. Namely an sliced access and an AT overlaying. There are of course old-school bit twiddling methods (masking, shifting and type casting) available as well.
	Regards, Jacek What is confusing you is the fact that you never see a number but always its digit representation. So you end up thinking that the number is the representation. - Andrej Bauer Any claims against me - based on whatever legal reason - resulting from the use of any code and/or ideas presented on this forum shall be excluded. #StayWithUkraine
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12/17/2024 1:04 PM	Rate (0)
Pekka.Hassinen Member Joined: 2/8/2022 Last visit: 12/17/2024 Posts: 1 Rating: (0)	DWORD -> 4x Bytes 24 bit +1 = 16777216 16 bit +1 = 65536 8 bit + 1 = 256 First I made sheet in excel. In example is 30 000 000 ( variable 'sum3' ) 30 000 000 / 16777216 = 1 ( variable 'VAL3') 30 000 000 - 1 * 16777216 = 13222784 ( SUM2) 13222784 / 65536 = 201 ( VAL2 ) 13222784 - 201 * 65536 = 50048 ( SUM1 ) 50048 / 256 = 195 ( VAL1) 50048 - 195 256 = 128 ( SUM0) 128 - 0 = 128 ( VAL0) check : 1 16777216 + 210 * 65536 + 195 * 256 + 128 = 30000000 written in IEC statement list ( not copy paste but math is same:) ( this give values in online : VAL3 = 1 VAL2 = 201 VAL1 = 195 VAL0 = 128 ...so it same values than excel, so it must be correct.... ################################## FUNCTION_BLOCK POKE VAR_INPUT ENA: BOOL; PAR: BYTE; VALUE: DWORD; CH: BYTE; END_VAR VAR_OUTPUT END_VAR VAR DATAA : ARRAY [0..7] OF BYTE; VAL0, VAL1, VAL2, VAL3 : BYTE; SUM0, SUM1, SUM2, SUM3: DWORD; END_VAR (* ##### dword --> byte x 4 ###) SUM3 := value; VAL3 := DWORD_TO_BYTE(SUM3 / 16777216 ); SUM2 := SUM3 - (VAL3 16777216 ); VAL2 := DWORD_TO_BYTE( SUM2 / 65536 ); SUM1 :=SUM2 - ( VAL2 * 65536 ); VAL1 := DWORD_TO_BYTE( SUM1 / 256 ); SUM0 :=SUM2 - ( VAL1 * 256 ); VAL0 := DWORD_TO_BYTE( SUM0 ) ; Attachment DWORD_TO_BYTES.jpg (182 Downloads)

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12/17/2024 1:19 PM	Rate (0)
jacek d Platinum Expert Joined: 9/23/2005 Last visit: 9/8/2025 Posts: 5112 Rating: (768)	OT Example of a MOD operator application: Pekka.Hassinen 13222784 / 65536 = 201 ( VAL2 ) 13222784 - 201 * 65536 = 50048 ( SUM1 ) 13222784 MOD 65536 = 50048 ( SUM1 )
	Regards, Jacek What is confusing you is the fact that you never see a number but always its digit representation. So you end up thinking that the number is the representation. - Andrej Bauer Any claims against me - based on whatever legal reason - resulting from the use of any code and/or ideas presented on this forum shall be excluded. #StayWithUkraine
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