Loop in Loop with STL

Dear all,

can you please explain below logic for me:

i want to know what happen in each cycle and what does BEU do? and how is the value of ACC1 and ACC2.

very thanks

jacek d

This is not a loop. This is jump list. Depending on ACC1 value label is selected and jump is executed. Program execution is resumed from there.

BEU returns from the blocks. ACC1 is equal to the value loaded after jump. ACC2 as usual after load instruction.

 Hi Mr.Jacek

thank you somuch for your response.

i want to know clearly that after executing first line, load Coe1 to ACC1 then execute BEU, does it go out of this block or goes back to the next jump???

if yes, after executing all of the Coe, load last Coe to ACC1???

if  no, after executing first jump and load first Coe, go out of block and in next cycle of OB go inside and execute first jump again???

please explain more clearly.

thanks alot

BEA/BEU (Block End Unconcitional/Bausteinende Absolut).

So, after jumping f.e. to So02: 

the programm execute  "Annealer Coeficient".Speed_Thre[2]

and the  programm ends here. 

Shahab_6448015

Hi Mr.Jacek

thank you somuch for your response.

i want to know clearly that after executing first line, load Coe1 to ACC1 then execute BEU, does it go out of this block or goes back to the next jump???

if yes, after executing all of the Coe, load last Coe to ACC1???

if  no, after executing first jump and load first Coe, go out of block and in next cycle of OB go inside and execute first jump again???

please explain more clearly.

thanks alot

The code delivers a multiplexing function, where one of 10 options are selected. Only 1 option is chosen. The functionality of the JL is close to the 'case' instruction. See the attachment for a description of the JL instruction.

The JL instruction processes an INT number. In this case from 0 (So01) to 9 (So10). The "Def" label is the default when the number is not between 0 and 9. In this case it means that So01 is the default.

On reaching the BEU instruction, the FC/FB ends. This is strange for the code -- the selected value that is loaded is not consumed. Perhaps the following idea is more appropriate.. 

qwazee

 

Shahab_6448015

Hi Mr.Jacek

thank you somuch for your response.

i want to know clearly that after executing first line, load Coe1 to ACC1 then execute BEU, does it go out of this block or goes back to the next jump???

if yes, after executing all of the Coe, load last Coe to ACC1???

if  no, after executing first jump and load first Coe, go out of block and in next cycle of OB go inside and execute first jump again???

please explain more clearly.

thanks alot

The code delivers a multiplexing function, where one of 10 options are selected. Only 1 option is chosen. The functionality of the JL is close to the 'case' instruction. See the attachment for a description of the JL instruction.

The JL instruction processes an INT number. In this case from 0 (So01) to 9 (So10). The "Def" label is the default when the number is not between 0 and 9. In this case it means that So01 is the default.

On reaching the BEU instruction, the FC/FB ends. This is strange for the code -- the selected value that is loaded is not consumed. Perhaps the following idea is more appropriate.. 

L     #SEL // input parameter / INT / selector

JL    Def

JU    So01

JU    So02

JU    So03

JU    So04

JU    So05

JU    So06

JU    So07

JU    So08

JU    So09

JU    So10

Def:  NOP   0

So01: L     "Annealer Coeficient".Speed_Thre[1]

JU Done // BEU

So02: L     "Annealer Coeficient".Speed_Thre[2]

JU Done // BEU

So03: L     "Annealer Coeficient".Speed_Thre[3]

JU Done // BEU

So04: L     "Annealer Coeficient".Speed_Thre[4]

JU Done // BEU

So05: L     "Annealer Coeficient".Speed_Thre[5]

JU Done // BEU

So06: L     "Annealer Coeficient".Speed_Thre[6]

JU Done // BEU

So07: L     "Annealer Coeficient".Speed_Thre[7]

JU Done // BEU

So08: L     "Annealer Coeficient".Speed_Thre[8]

JU Done // BEU

So09: L     "Annealer Coeficient".Speed_Thre[9]

JU Done // BEU

So10: L     "Annealer Coeficient".Speed_Thre[10]

// BEU

Done: T      #OUT  // output parameter / REAL / result

What is Coe1 and Coe? 

 Hi Sir,

Thank you so much.

it is clear

qwazee

This is strange for the code -- the selected value that is loaded is not consumed.

I've seen this way of coding. This piece of code is usually an FC without interface and takes whatever ACC1 happens to be prior the code is called then leaves the result there and quits. The value is consumed outside.

But you are right, it looks strange nowadays.

jacek d

 

qwazee

This is strange for the code -- the selected value that is loaded is not consumed.

I've seen this way of coding. This piece of code is usually an FC without interface and takes whatever ACC1 happens to be prior the code is called then leaves the result there and quits. The value is consumed outside.

But you are right, it looks strange nowadays.

The thought did occur to me, which I ignored because I was trained to NEVER use that technique. It must have been popular with the S5 professionals.

So now I wondered if this is still doable in the S7-1500.

First then the base example for the S7-300 (see picture).
 

Ported over to the S7-1500 (see picture).

Conclusion is that the compiler does not allow this technique. But then we also know that the S7-1500 emulates the use of accumulators. Moreso.. STL is best avoided in the S7-1500.

~

Actually it was quite useful technique in STL programming. It allowed creation of FCs which worked like STL instructions.

And it still is possible in TIA. Even in S7-1500. Search for "Parameter assignment via registers during block call in STL" in online help.

jacek d

Actually it was quite useful technique in STL programming. It allowed creation of FCs which worked like STL instructions.

And it still is possible in TIA. Even in S7-1500. Search for "Parameter assignment via registers during block call in STL" in online help.

   .. that is exactly what I missed.