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STEP 5 instruction in STEP 7

Created by: mr.adi at: 9/13/2016 4:58 PM (11 Replies)

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9/13/2016 4:58 PM	Rate (0)
mr.adi Posts: 112 Rating: (0)	Hello guys I will write a program on step 7 from step 5 examples. I have some operation that i can not find on step 7, if anyone has made something like that can help me? For example "DO operation" on step 5. how can i find one instruction on step 7 that can replace it? Thanks Best regards Adi ------------------------------------------------------------------------------------------ Split from Convert program from step5 to step7 .
mr.adi Posts: 112 Rating: (0)	Last edited by: Min_Moderator at: 9/14/2016 12:55:39 PM New subject after splitting
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9/13/2016 6:49 PM	Rate (1)
mindware Platinum Member Joined: 3/30/2011 Last visit: 11/19/2024 Posts: 736 Rating: (258)	Hello, attacched to previous post there is a document with complete list of instruction for S5 and S7 (for both english and german mnemonics, see appendix A). About DO instruction see here for some info.... Best Regards
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9/14/2016 11:16 AM	Rate (0)
mr.adi Posts: 112 Rating: (0)	Thanks for your answer It was very helpful, another operands that i want to convert is DL"data word (left hand byte)" and DR "data word (right hand byte)" How can i replace on step 7? Best regards Adi
mr.adi Posts: 112 Rating: (0)
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This contribution was helpful to 1 thankful Users mindware

9/14/2016 1:34 PM	Rate (0)
Ronaldo Junior Experienced Member Joined: 2/22/2008 Last visit: 10/16/2024 Posts: 59 Rating: (6)	Dear mr.adi, See one example of how to convert operation such as DL and DR: S5: DL MW100 S7: L MB100 S5: DR MW100 S7: L MB101 This means that you have to understand what is the left and right bytes of your word which is being manipulated with DL and DR operation. Hope it helps.
	Best Regards Ronaldo Schittini Gardoni Junior Primetals Technologies ------------------------------------- Helpful? Rate it. Solved? Post it.
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9/14/2016 2:01 PM	Rate (0)
mr.adi Posts: 112 Rating: (0)	Thanks for your answer I have this case on step 5 :L DL 77 :L KF 1 :+F :T DL 77 And i create on this way L MB 77 L 1 +I T MB 77 I am not sure if this is the right way. Best regards Adi
mr.adi Posts: 112 Rating: (0)
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9/14/2016 2:13 PM	Rate (0)
ixo65 Grandmaster Joined: 12/18/2014 Last visit: 12/4/2024 Posts: 34334 Rating: (4276)	My solution propospal for STEP7 in STL // Data Left DB1, DW78 L DB1.DBB 78 L 1 +I T DB1.DBB 78 // Data Right DB1, DW78 L DB1.DBB 79 L 1 +I T DB1.DBB 79

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9/14/2016 2:23 PM	Rate (0)
mr.adi Posts: 112 Rating: (0)	Thanks for your answer You think that i must use two different data byte. One for the left hand byte and one for the right hand byte? Best regards Adi
mr.adi Posts: 112 Rating: (0)
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9/14/2016 2:48 PM	Rate (0)
ixo65 Grandmaster Joined: 12/18/2014 Last visit: 12/4/2024 Posts: 34334 Rating: (4276)	Yes. A data word has two data bytes, an left byte and an right byte. DL = Data byte left of a data word. DR = Data byte right of a data word.

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9/14/2016 5:21 PM	Rate (0)
mr.adi Posts: 112 Rating: (0)	Thanks for your answer ixo65 I appreciate your help Best regards Adi
mr.adi Posts: 112 Rating: (0)
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9/15/2016 9:05 AM	Rate (0)
mr.adi Posts: 112 Rating: (0)	Hello guys I have another data type that i want to replace. i have a idea but i am not sure // L KM 00000000 00011111 L IB 50 AW ==I = M 40.2 My idea is to replace with integer number L 31 L IB 50 AW ==I = M 40.2 I try in simulation and it works. Best regards Adi
mr.adi Posts: 112 Rating: (0)
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