Skip to Content

Register Login

Industry Online Support

Technical Forum

Navigation

Message R9200 after motor burnt! help

Created by: chteng at: 7/6/2010 5:16 AM (13 Replies)

Rating (0)

Thanks 0

Result pages:: |; 1 | 2; |

14 Entries

Entries per page: 10 | all

7/9/2010 12:14 PM	Rate (0)
JensS Posts: 739 Rating: (55)	A0922 = No load applied to inverter A0922 is an alarm, not a failure. With an alarm the inverter will not switched OFF! If you need to have that, you have to parametrize / wire this. Yes it is possible that this alarm is displayed when one of the motor coils is “burnt”, but it is not the reason of this burnt coil. This alarm is displayed, when the actual motor current is less than 3% (P2179 - Factory Set). - It may be that the motor is not connected properly, e.g. a phase could be missing (= burnt coil). The reason of this burnt coil could be a: - bad power cable connection between motor and inverter. - defect contactor (if you are using one) between motor and inverter. - a bad / wrong coil insulation (is the motor certified for inverter?) - a missing / defect output phase of the inverter Explanation: When one of the motor phase is not properly connected, ore missing, than the inverter will feed the motor via the remaining two phase. This brings a lot more current, inside the motor, as the motor coils can handle. The inverter will not see the missing phase, but after a wile A0922 is displayed.
JensS Posts: 739 Rating: (55)
Suggestion To thank Quote Answer

7/9/2010 12:47 PM	Rate (0)
Vithani Platinum Expert Joined: 7/8/2009 Last visit: 8/5/2024 Posts: 1976 Rating: (477)	JensS A0922 = No load applied to inverter A0922 is an alarm, not a failure. With an alarm the inverter will not switched OFF! If you need to have that, you have to parametrize / wire this. Yes it is possible that this alarm is displayed when one of the motor coils is “burnt”, but it is not the reason of this burnt coil. This alarm is displayed, when the actual motor current is less than 3% (P2179 - Factory Set). - It may be that the motor is not connected properly, e.g. a phase could be missing (= burnt coil). The reason of this burnt coil could be a: - bad power cable connection between motor and inverter. - defect contactor (if you are using one) between motor and inverter. - a bad / wrong coil insulation (is the motor certified for inverter?) - a missing / defect output phase of the inverter Explanation: When one of the motor phase is not properly connected, ore missing, than the inverter will feed the motor via the remaining two phase. This brings a lot more current, inside the motor, as the motor coils can handle. The inverter will not see the missing phase, but after a wile A0922 is displayed. Well Jens, As per chteng's last post, he is using output contactor. Now what I am thinking is, he has some problem in control logic. He might shutdown the motor along with contactor. In such case, motor will stop by it self and drive will ramp down and will get A0922 because of open contactor. Contactor should not be operated while drive is still supplying power to motor Because of On Load switching of contactor at output of drive, motor is being damaged.. As per FAQ, drive must be in Off condition either OFF1 or OFF2 before operating contactor Here are some links from google regarding output contactor.... http://forums.mikeholt.com/archive/index.php/t-85580.html http://www.ctiautomation.net/AC-Tech-Drives-FAQs.htm http://www.allinterview.com/showanswers/74168.html http://www.industrial-electronics.com/output_devices_amplifiers_valves_relays_variable-frequency_drives_stepper_motors_servomotors/AC-drives-FAQ-3.html Regards, Devesh Vithani
	Last edited by: Vithani at: 7/9/2010 1:58 PM Last edited by: Vithani at: 7/9/2010 1:57 PM I dont Like people driving Fast, thats the reason I overtake them ;)
Suggestion To thank Quote Answer

7/13/2010 5:22 PM	Rate (0)
Vitas Posts: 74 Rating: (2)	In the standard application is recommended not use output contactor, but some application required contactor of safety reasons. In this caseis better waycontrol the output contactor directly by MM440 outputtogether with internal BI-CO parametrisation (free programming blocks). Safety relay contact connect to Dig. Input of MM440and configure thisas theOFF3 signal. Vitas
Vitas Posts: 74 Rating: (2)
Suggestion To thank Quote Answer

8/5/2010 7:15 PM	Rate (0)
JullioC Posts: 16 Rating: (1)	Hello What I see is that maybe you are using incorrect configuration of Drive. please check the following parameters: 1. P0300 Select motor type 1 Asynchronous motor (induction motor) 2 Synchronous motor 2. p0304 Rated motor voltage (Nominal motor voltage [V] from rating plate) The rated motor voltage on the rating plate must be checked, regarding the star/delta circuit configuration toensure that it matches with the circuitconnection configured at the motor terminal board 3. p0305 Rated motor current (Nominal motor current [A] from rating plate 4. p0307 Rated motor power (Nominal motor power [kW/hp] from rating plate) If P0100 = 0 or 2, value will be in kW. If P0100 = 1, value will be in in hp. 5. P0640 Motor overload factor (Motor overload factor in [%] relative to P0305) This defines the limit of the maximum output current as a % of the rated motor current (P0305). This parameter is set, using P0205 for constant torque, to 150 %, and for variable torque, to 110 %. you must notice that the motor was rewired, then it could support less current, because is easier to rewire whit a wire with less diameter if you could eliminate teh downstream contactor will be excellent. i hope that it was helpfull. Julio
JullioC Posts: 16 Rating: (1)
Suggestion To thank Quote Answer

|

Share this page:

Share this page on...

Follow us on